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Juli2301 [7.4K]
2 years ago
5

PLEASE HELP ME I REALLY NEED HELP

Physics
1 answer:
allochka39001 [22]2 years ago
3 0

Answer:

The answer is A.

Explanation:

The graph would show the unit rate otherwise known as a ratio

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A 250 g block of ice is removed from the refrigerator at -8.0°C. How much thermal energy does the ice absorb as it warms to room
zlopas [31]

Answer:

Q = 114895 J

Explanation:

To find the thermal energy gained by the ice you use the following formula:

Q=mc(T_2-T_1)+H_f\ m

m: mass of the ice = 0.250kg

T2: final temperature = 22°C

T1: initial temperature = -8.0°C

Hf: heat of fusion of water = 3.34*10^5 J/kg

c: specific heat of water = 4186 J/kg

By replacing the values of the parameters you have:

Q=(0.250kg)(4186J/kg\°C)(22+8)\°C+(3.34*10^5 J/kg)(0.250kg)\\\\Q=114895\ J

where you have considered that ice melts completely

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4 years ago
A heat engine is a device that uses<br> to produce useful work.
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A heat engine <em>is </em>a device that uses to produce useful work.

Definition - a device for producing motive power from heat, such as a gasoline engine or steam engine.

So..

If this is a true or false question.. Your answer is:

TRUE

Hope this helps!

- Kylie

7 0
3 years ago
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What is the relationship between particles in soil and flow of water in soil
maxonik [38]
<span>In general the larger the pore space (the higher the porosity) the easier it is</span>
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3 years ago
A 0.45 m radius, 500 turn coil is rotated one-fourth of a revolution in 4.01 ms, originally having its plane perpendicular to a
AysviL [449]

Answer:

B = 0.126 T

Explanation:

As per Faraday's law we know that rate of change in magnetic flux will induce EMF in the coil

So here we can say that EMF induced in the coil is given as

EMF = \frac{\phi_2 - \phi_1}{\Delta t}

initially the coil area is perpendicular to the magnetic field

and after one fourth rotation of coil the area vector of coil will be turned by 90 degree

so we can say

\phi_1 = NBAcos 0 = BA

\phi_2 = NBAcos 90 = 0

now we will have

EMF = \frac{NBA}{t}

10,000 V = \frac{(500)(B)(\pi \times 0.45^2)}{4.01\times 10^{-3}}

B = 0.126 T

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