Answer:
The work done by the worker on the crate is 4830 J.
Explanation:
Given that,
Force = 1080 N
Horizontal force = 345 N
Distance d = 14 m
Coefficient of friction = 0.22
We need to calculate the work done
Using formula of work done
F = force
d = distance
Put the value into the formula
Hence, The work done by the worker on the crate is 4830 J.
Answer:
n the case of linear motion, the change occurs in the magnitude of the velocity, the direction remaining constant.
In the case of circular motion, the magnitude of the velocity remains constant, the change in its direction occurring.
Explanation:
Velocity is a vector therefore it has magnitude and direction, a change in either of the two is the consequence of an acceleration on the system.
In the case of linear motion, the change occurs in the magnitude of the velocity, the direction remaining constant.
= (v₂-v₁)/Δt
In the case of circular motion, the magnitude of the velocity remains constant, the change in its direction occurring.
= v2/R
In the general case, both the module and the address change
a = Ra ( a_{t}^2 + a_{c}^2)