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Agata [3.3K]
4 years ago
12

Suppose Galileo and his assistant were 1 km apart when Galileo uncovered his lantern to try to measure the speed of light. How l

ong would it have taken the light signal to reach his assistant?
Physics
1 answer:
Black_prince [1.1K]4 years ago
4 0
The speed of light is approximately 3.00 x 10^8 m/s. Then the next step is to convert m/s into km/s.To determine the time, the distance must be divided with velocity. It will take the light signal 3.3*10^-6 seconds to reach his assistant.
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If the ball is stationary just before it is hit and goes 5.40 m high, what impulse did she impart to it?
weeeeeb [17]

Energy is conserved. If the ball reaches a height of 5.50 m, it has gained a certain amount of gravitational potential energy. That energy had to come from somewhere. From this fact, you can deduce the speed of the ball at the end of the impact with the racket.

<h3>What is gravitational potential energy?</h3>

Gravitational energy or gravitational potential energy is the potential energy a huge item has corresponding to one more monstrous article because of gravity. It is the potential energy related with the gravitational field, which is delivered (changed over into active energy) when the articles fall towards one another. Gravitational potential energy increments when two articles are brought further apart. It is the potential energy related with the gravitational field, which is delivered (changed over into dynamic energy) when the items fall towards one another. Gravitational potential energy increments when two items are brought further separated.

Learn more about gravitational potential energy, visit

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3 0
1 year ago
At room tmeperature none of the metals are
Masja [62]

What metal is not at room temperature?

Mercury is a metallic chemical element that is an only metal that is not a solid at room temperature.

6 0
2 years ago
A point charge of magnitude q is at the center of a cube with sides of length L.a) What is the electric flux through each of the
agasfer [191]
<h2>The flux through each face is q/6ε₀ .</h2>

Explanation:

The charge q is placed at the center of the cube of side L

According to Gauss's law the flux through any closed surface is q/ε₀

here q is the charge enclosed .

In this case cube has the six faces . The flux through each face = q/6ε₀

In the second case The cube has the face with length L₁

The flux through each face = q/6ε₀

Thus flux through the cube does not depend upon the size of the cube .

3 0
3 years ago
Consider a steel guitar string of initial length L=1.00L=1.00 meter and cross-sectional area A=0.500A=0.500 square millimeters.
erma4kov [3.2K]

Answer:

The extent to which it would stretch  is \Delta L = 0.015 \ m

Explanation:

From the question we are told that

    The initial length is  L = 1.00m

     The area is  A = 0.500 mm^2 = \frac{0.500}{1 *10^6} = 0.500*10^6 \ m^2

     The Young modulus of the steel is  Y = 2.0*10^{11} Pa

     The tension   is  T =1500 N

The Young modulus is mathematically represented as

       Y = \frac{\sigma}{e}

Where \sigma is the stress which is mathematically represented as

           \sigma = \frac{F}{A}  

Substituting values

            \sigma = \frac{1500}{0.500*10^{-6}}  

           \sigma = 3.0*10^9 N/m^2  

And  e is the strain which is mathematically represented as

            e = \frac{\Delta L}{L }

Where \Delta L The extension of the steel string

Substituting these into the equation above

             Y = \frac{3.0*10^9}{\frac{\Delta L}{L} }

Substituting values  

           2.0 *10^{11} = \frac{3.0*10^9}{\frac{\Delta L}{L} }

          \Delta L = \frac{3.0*10^9  * 1}{2.0 *10^{11}}

         \Delta L = 0.015 \ m

7 0
3 years ago
3. Order the following lengths from shortest to longest.
horrorfan [7]

Answer: d < a < c < b

3.3 cm < 400 mm < 170 m < 22 km

Explanation:

Firstly, let's convert these length to meters m, in order to work with the same units:

a. 400 millimeters

400 mm \frac{1m}{1000 mm}=0.4 m

b. 22 kilometers

22 km \frac{1000m}{1 km}=22000 m

c. 170 meters

Here the lenght is already in meters

d. 3.3 centimeters

3.3 cm \frac{1m}{100 cm}=0.033 m

Now that we have all the lengths in meters, we can order them from shortest to longest:

0.033 m < 0.4 m < 170 m < 22000 m

or

d < a < c < b

7 0
4 years ago
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