1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Aleks04 [339]
1 year ago
5

FILL IN THE BLANK. immediately following the arrival of the stimulus at a skeletal muscle cell there is a short period called th

e __ period during which the events of excitation-contraction coupling occur.
Physics
1 answer:
Marrrta [24]1 year ago
6 0

Immediately following the arrival of the stimulus at a skeletal muscle cell, there is a short period called the latent period during which the events of excitation-contraction coupling occur.

This process is a connection between transduction in the sarcolemma and the initiation of muscle contraction. Sarcolemma is nothing but the cell membrane of skeletal muscle.

A single muscle twitch has a latent period, a contraction phase when tension increases and a relaxation phase when tension decreases.

The period of incubation, the interval preceding exposure to a pathogen toxin or radiation, and when effects occur. Muscle contracting, the time between a nerve stimulus and muscle contraction.

To know more about muscles:

brainly.com/question/13753345

#SPJ4

You might be interested in
The figure shows a 100-kg block being released from rest from a height of 1.0 m. It then takes it 0.90 s to reach the floor. Wha
Anna007 [38]

Answer:

The mass of the another block is 60 kg.

Explanation:

Given that,

Mass of block M= 100 kg

Height = 1.0 m

Time = 0.90 s

Let the mass of the other block is m.

We need to calculate the acceleration of each block

Using equation of motion

s=ut+\dfrac{1}{2}at^2

Put the value into the formula

1.0=0+\dfrac{1}{2}\times a\times(0.90)^2

a=\dfrac{2\times1.0}{(0.90)^2}

a=2.46\ m/s^2

We need to calculate the mass of the other block

Using newton's second law

The net force of the block M

Ma=Mg-T

T=Mg-Ma....(I)

The net force of the block m

ma=T-mg

Put the value of T from equation (I)

ma=Mg-Ma-mg

m(a+g)=M(g-a)

m=\dfrac{M(g-a)}{(a+g)}

Put the value into the formula

m=\dfrac{100(9.8-2.46)}{2.46+9.8}

m=59.8\ \approx60\ kg

Hence, The mass of the another block is 60 kg.

8 0
3 years ago
In a collision, a 25.0 kg mass moving at 3.0 m/s transfers all of its momentum to a 5.0 kg mass.
nadezda [96]

Answer:

Explanation:

The momentum of the 25 kg mass is

p=mv

p=25kg*3m/s= 75kg*m/s

If this whole momentum of the object is transferred to the 5.0 kg object then according to the law of conservation of momentum, the momentum of the 25.0 kg object must be transferred to the 5.0 kg object:

75kg*m/s = 5.0kg*v

v=\dfrac{75}{5}

\boxed{v=15m/s}

8 0
3 years ago
A 91.5 kg football player running east at 2.73 m/s tackles a 63.5 kg player running east at 3.09 m/s. what is their velocity aft
vivado [14]

Their velocity afterwards is 2.88 m/s east

Explanation:

We can solve this problem by using the law of conservation of momentum. In fact, for an isolated system (= no external force), the total momentum must be conserved before and after the collision. So we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1 + m_2)v

where: in this case:

m_1 = 91.5 kg is the mass of the first player

u_1 = 2.73 m/s is the initial velocity of the first player (choosing east as positive direction)

m_2 = 63.5 kg is the mass of the second player

u_2 = 3.09 m/s is the initial velocity of the second player

v is their combined velocity afterwards

Solving for v, we find:

v = \frac{m_1 u_1+m_2 u_2}{m_1+m_2}=\frac{(91.5)(2.73)+(63.5)(3.09)}{91.5+63.5}=2.88 m/s

And the sign is positive, so the direction is east.

Learn more about momentum here:

brainly.com/question/7973509  

brainly.com/question/6573742  

brainly.com/question/2370982  

brainly.com/question/9484203  

#LearnwithBrainly

7 0
3 years ago
A source at rest emits light of wavelength 500 nm. When it is moving at 0.90c toward an observer, the observer detects light of
Vesna [10]

Answer:

The observer detects light of wavelength is 115 nm.

(b) is correct option

Explanation:

Given that,

Wavelength of source = 500 nm

Velocity = 0.90 c

We need to calculate the wavelength of observer

Using Doppler effect

\lambda_{o}=\sqrt{\dfrac{1-\beta}{1+\beta}}\lambda_{s}

Where, \beta=\dfrac{c}{v}

\lambda_{o}=\sqrt{\dfrac{c-0.90c}{c+0.90c}}\times500\times10^{-9}

\lambda_{o}=115\ nm

Hence, The observer detects light of wavelength is 115 nm.

8 0
4 years ago
What is the sharpness of the light and the amount of voltage when you put the magnet through the lower number of coils first vs
fomenos

Answer:hjvuihi

Explanation:lk

4 0
3 years ago
Other questions:
  • To which layer can geologists apply the principle of faunal succession to determine the age of the layer?
    12·2 answers
  • How does deformation by drawing of a semicrystalline polymer affect its tensile strength?
    9·1 answer
  • 1. A giri rides her bike at 15 m/s for 20 s. How far does she travel in that time?
    6·2 answers
  • A hockey puck with a mass of 0.17 kg is traveling to the right along the ice at 15 m/s. it strikes a second hockey puck with a m
    11·1 answer
  • I need help with the 1st and the 3rd one plzzzzzzzzzzzzz
    13·1 answer
  • Owen is going on a multi-day hike up a large mountain. He wants to know what clothes he should bring for the higher elevation as
    15·2 answers
  • Which scientist discovered the laws that determine the motion of a spring?
    9·1 answer
  • How are electromagnetic waves used in a bar-code scanner?
    11·1 answer
  • a charged partocle produces an electric field with a magnitude of 2.0 N/C at a point that is 50cm away from the particle
    7·1 answer
  • A roller coaster, traveling with an initial speed of 21 m/s, decelerates uniformly at -3.5
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!