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Aleks04 [339]
1 year ago
5

FILL IN THE BLANK. immediately following the arrival of the stimulus at a skeletal muscle cell there is a short period called th

e __ period during which the events of excitation-contraction coupling occur.
Physics
1 answer:
Marrrta [24]1 year ago
6 0

Immediately following the arrival of the stimulus at a skeletal muscle cell, there is a short period called the latent period during which the events of excitation-contraction coupling occur.

This process is a connection between transduction in the sarcolemma and the initiation of muscle contraction. Sarcolemma is nothing but the cell membrane of skeletal muscle.

A single muscle twitch has a latent period, a contraction phase when tension increases and a relaxation phase when tension decreases.

The period of incubation, the interval preceding exposure to a pathogen toxin or radiation, and when effects occur. Muscle contracting, the time between a nerve stimulus and muscle contraction.

To know more about muscles:

brainly.com/question/13753345

#SPJ4

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Mr. Barcena reached a top speed of 5m/s in 2 seconds from rest, what was his average acceleration including units?
sashaice [31]

Answer:

Explanation:

The equation for acceleration is

a=\frac{v_f-v_0}{t} where vf is the final velocity and v0 is the initial velocity. Filling in:

a=\frac{5-0}{2} so

a = 2.5 m/s/s

4 0
2 years ago
100 meters toward the shore in 25 seconds
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Answer:

The speed of a turtle is 4m/s

Explanation:

speed = distance/time

distance = 100m

time = 25s

s = 100/25

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6 0
3 years ago
Please help asap I need this rn
den301095 [7]
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3 years ago
An astronaut goes to Mars to do some experiments. Explain why her mass stays the same but her weight changes.
Snowcat [4.5K]
Because mass does not change from place to place but weight does change from place to place... why? because weight is the amount of gravitational force on an object and mass is the amount of matter in an object. mars has less gravitational force so an object will weigh less than it really weighs there
6 0
2 years ago
The kinetic energy of a moving object is E=12mv2. A 61 kg runner is moving at 10kmh. However, her speedometer is only accurate t
jek_recluse [69]

Answer:

e=3367.2J

%e=1.43%

Explanation:

From the exercise we know two information. The real speed and the experimental measured by the speedometer

v_{r}=10km/h=2.77m/s

Since the speedometer is only accurate to within 0.1km/h the experimental speed is

v_{e}=10km/h-0.1km/h=9.9km/h=2.75m/s

Knowing that we can calculate Kinetic energy for the real and experimental speed

E_{r}=\frac{1}{2}mv^2=\frac{1}{2}(61000g)(2.77m/s)^2=234023J

E_{e}=\frac{1}{2}mv^2=\frac{1}{2}(61000g)(2.75m/s)^2=230656J

Now, the potential error in her calculated kinetic energy is:

e=E_{r}-E_{e}=(234023-230656)J=3367.2J

%e=\frac{E_{r}-E_{e}}{E_{r}}x100=\frac{(234023-230656)J}{234023J}x100=1.43%

4 0
3 years ago
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