People, and cars
is the right answer!!!!!!!!!!!!!!!!!!!!!!!!!!
m = mass = 1,200 kg
A = acceleration = 3 m/s^2
Apply Newton's second law:
Force = mass x acceleration
F = 1,200 x 3 =3600 N
The net force the car experiences is 3600 N
Answer:
The displacement of the car after 6s is 43.2 m
Explanation:
Given;
velocity of the car, v = 12 m/s
acceleration of the car, a = -1.6 m/s² (backward acceleration)
time of motion, t = 6 s
The displacement of the car after 6s is given by the following kinematic equation;
d = ut + ¹/₂at²
d = (12 x 6) + ¹/₂(-1.6)(6)²
d = 72 - 28.8
d = 43.2 m
Therefore, the displacement of the car after 6s is 43.2 m
By ideal gas theory, cylinder b has the higher temperature.
We need to know about the ideal gas theory to solve this problem. The ideal gas can be represented by
P . V = n . R . T
where P is the pressure, V is volume, n is the number of molecules, R is the ideal gas constant and T is temperature.
From the question above, we know that
Pa = Pb = P
na = 3nb
Find the temperature of the cylinder a
P . V = n . R . Ta
Ta = P . V /( na . R )
Substitute na
Ta = P . V /( (3nb) . R )
Ta = (1/3) x (P . V /( (nb . R ))
Find the temperature of the cylinder b
P . V = n . R . Tb
Tb = P . V /( nb . R )
The cylinder a temperature is 3 times smaller than the temperature in cylinder b.
Find more on ideal gas at: brainly.com/question/25290815
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