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Arturiano [62]
3 years ago
14

4. Describe how the velocity of an object changes if it undergoes uniformly acceleration motion. Can its direction change?

Physics
1 answer:
valentinak56 [21]3 years ago
4 0

Answer:

n the case of linear motion, the change occurs in the magnitude of the velocity, the direction remaining constant.

In the case of circular motion, the magnitude of the velocity remains constant, the change in its direction occurring.

Explanation:

Velocity is a vector therefore it has magnitude and direction, a change in either of the two is the consequence of an acceleration on the system.

In the case of linear motion, the change occurs in the magnitude of the velocity, the direction remaining constant.

              a_{t} = (v₂-v₁)/Δt

In the case of circular motion, the magnitude of the velocity remains constant, the change in its direction occurring.

                    a_{c} = v2/R

In the general case, both the module and the address change

             a = Ra (  a_{t}^2 +   a_{c}^2)  

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Name two things that the people standing on the street corner would say are in motion
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3 years ago
A 1,200 kg car accelerates at 3 m/s2. What net force is the car experiencing during thisacceleration?0 3600 NO 2000 N0 2400 NOON
Mama L [17]

m = mass = 1,200 kg

A = acceleration = 3 m/s^2

Apply Newton's second law:

Force = mass x acceleration

F = 1,200 x 3 =3600 N

The net force the car experiences is 3600 N

5 0
1 year ago
A car moves forward up a hill at 12 m/s with a uniform backward acceleration of 1.6 m/s2. What is its displacement after 6 s?
Romashka [77]

Answer:

The displacement of the car after 6s is 43.2 m

Explanation:

Given;

velocity of the car, v = 12 m/s

acceleration of the car, a = -1.6 m/s² (backward acceleration)

time of motion, t = 6 s

The displacement of the car after 6s is given by the following kinematic equation;

d = ut + ¹/₂at²

d = (12 x 6) + ¹/₂(-1.6)(6)²

d = 72 - 28.8

d = 43.2 m

Therefore, the displacement of the car after 6s is 43.2 m

6 0
3 years ago
Two identical cylinders at the same pressure contain the same gas. if cylinder a contains three times as much gas as cylinder b,
Alborosie

By ideal gas theory, cylinder b has the higher temperature.

We need to know about the ideal gas theory to solve this problem. The ideal gas can be represented by

P . V = n . R . T

where P is the pressure, V is volume, n is the number of molecules, R is the ideal gas constant and T is temperature.

From the question above, we know that

Pa = Pb = P

na = 3nb

Find the temperature of the cylinder a

P . V = n . R . Ta

Ta = P . V /( na . R )

Substitute na

Ta = P . V /( (3nb) . R )

Ta = (1/3) x (P . V /( (nb . R ))

Find the temperature of the cylinder b

P . V = n . R . Tb

Tb = P . V /( nb . R )

The cylinder a temperature is 3 times smaller than the temperature in cylinder b.

Find more on ideal gas at: brainly.com/question/25290815

#SPJ4

5 0
2 years ago
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