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Kaylis [27]
3 years ago
15

Help-! please, im really struggling here-

Mathematics
2 answers:
Luda [366]3 years ago
8 0

Answer:

• let these consecutive numbers have a variable x

  • first number → x
  • second number → 2x
  • third number → 3x

\hookrightarrow \: { \rm{ \: x + 2x + 3x =  - 354}} \\  \\ { \rm{6x =  - 354}} \\  \\ { \rm{x =  - 59}}

→ The integers are -59, -118, -117

Ket [755]3 years ago
3 0

Answer: -300,-50,-4

Step-by-step explanation:

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2 years ago
Convert the equation to the standard form for a hyperbola 4x^2-25y^2-8x+50y-121=0
S_A_V [24]
We have that
4x²-25y²<span>-8x+50y-121=0

</span><span>Group terms that contain the same variable, and move the constant to the opposite side of the equation
</span>(4x²-8x)+(-25y²+50y)=121

Factor the leading coefficient of each expression
4(x²-2x)-25(y²-2y)=121

Complete the square twice. Remember to balance the equation by adding the same constants to each side.
4(x²-2x+1)²-25(y²-2y+1)²=121+4-25

Rewrite as perfect squares
4(x-1)²-25(y-1)²=100

<span>Divide both sides by the constant term to place the equation in standard form</span>
(4/100)(x-1)²-(25/100)(y-1)²=100/100
(1/25)(x-1)²-(1/4)(y-1)²=1

[(x-1)²]/25-[(y-1)²]/4=1

the answer is
[(x-1)²]/25-[(y-1)²]/4=1


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Step-by-step explanation:

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