Answer:For these, n is equal to the term you want. So you substitute the number in for whichever term you want. This means:
a) 1 (1st term) + 5 = 6
2 (2nd term) + 5 = 7
3 (3rd term) + 5 = 8
4 (4th term) + 5 = 9
10 (10th term) + 5 = 15
And so on for b (not going to keep writing the term, I’m sure you get that by now.
b) 2(1) - 1 = (2x1) - 1 = 1
2(2) - 1 = (2x2) - 1 = 3
2(3) - 1 = (2x3) - 1 = 5
2(4) - 1 = (2x4) - 1 = 7
2(10) - 1 = (2x10) - 1 = 19
Hope this helps :)
Answer: ![\begin{bmatrix}\mathrm{Solution:}\:&\:x\le \frac{17}{3}\:\\ \:\mathrm{Decimal:}&\:x\le \:5.66666\dots \\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:\frac{17}{3}]\end{bmatrix}](https://tex.z-dn.net/?f=%5Cbegin%7Bbmatrix%7D%5Cmathrm%7BSolution%3A%7D%5C%3A%26%5C%3Ax%5Cle%20%5Cfrac%7B17%7D%7B3%7D%5C%3A%5C%5C%20%5C%3A%5Cmathrm%7BDecimal%3A%7D%26%5C%3Ax%5Cle%20%5C%3A5.66666%5Cdots%20%5C%5C%20%5C%3A%5Cmathrm%7BInterval%5C%3ANotation%3A%7D%26%5C%3A%28-%5Cinfty%20%5C%3A%2C%5C%3A%5Cfrac%7B17%7D%7B3%7D%5D%5Cend%7Bbmatrix%7D)
Step-by-step explanation:






I got 1.5, but I could be wrong.