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kolezko [41]
3 years ago
14

Question 9 of 10 Which inequality is shown in this graph?

Mathematics
1 answer:
Anestetic [448]3 years ago
5 0

Answer:

c

Step-by-step explanation:

the line is going down so we know it has to be a negative slope narrowing the answer choices down to a and c but when you pick a point to check for the reigon (i used 0,0 as a basic point) only c satisfies the inequality while keeping the point , not a.

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Y = mx + b, the letter b is the
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B is the Y-Intercept of the graph/equation

Step-by-step explanation:

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QUESTION 1<br> Given the equation of the circle (x + 7) + (y – 5) 2 = 64, identify the center.
o-na [289]

Answer:

center=(-7,5)

Step-by-step explanation:

The center form of the circle equation is in the format (x – h)^2 + (y – k)^2 = r^2, with the center being at the point (h, k).

you can find center by making equal to zero each term, then:

x+7 = 0

x=-7

y-5 = 0

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then the center is (-7,5).

6 0
3 years ago
Finch divides 12 peaches and 18 Nectarines into the same number of equal groups. How many possible groups of each fruit can he m
Naya [18.7K]

This question is based on prime factorization method.

As given there are 12 peaches and 18 nectarines

Factors of 12 are : 2,3,4,6 and 12

Factors of 18 are : 2,3,6,9 and 18

As mentioned, fruits are divided into the same number of equal groups, so the groups can be formed as-

1. 6 groups of peaches with 2 in each and 6 groups of nectarines with 3 in each,

2. 3 groups of peaches with 4 in each and 3 groups of nectarines with 6 in each.

3. 2 groups of peaches with 6 in each and 2 groups of nectarines with 9 in each.




7 0
2 years ago
Look at pic and answer pls
PtichkaEL [24]

(a)  x^{-5}

(b)  3x^{-7}

(c)  $\frac{4}{3}x^4

Solution:

To write each of the given expression in the form ax^n:

(a)  \frac{x^3}{x^8}

Using exponential rule: \frac{a^x}{a^y}=a^{x-y}

$\frac{x^3}{x^8}=x^{3-8}

$\frac{x^3}{x^8}=x^{-5}

(b) \frac{6x}{2x^8}

Divide numerator and denominator by the common factor 2, we get

$\frac{6x}{2x^8}=\frac{3x}{x^8}

Using exponential rule: \frac{a^x}{a^y}=a^{x-y}

      $=3x^{1-8}

$\frac{6x}{2x^8} =3x^{-7}

(c)  \frac{28x^6}{21x^2}

Divide numerator and denominator by the common factor 7, we get

$\frac{28x^6}{21x^2}=\frac{4x^6}{3x^2}

Using exponential rule: \frac{a^x}{a^y}=a^{x-y}

        $=\frac{4}{3}x^{6-2}

$\frac{28x^6}{21x^2}=\frac{4}{3}x^4

8 0
3 years ago
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