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padilas [110]
2 years ago
9

Help this is due tmr!!

Mathematics
1 answer:
Mumz [18]2 years ago
4 0

Answer:

A is correct

Step-by-step explanation:

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28 divided by 5 gvbhcjdxksalskdfjghnvjckfkckkvkvjv
Elina [12.6K]

Answer:

5.6

Step-by-step explanation:

HAve a nice day!

8 0
2 years ago
A square has an area of 144 sq. units. how long is its perimeter?
Arada [10]
Formula for Area of a square:

\boxed {\boxed {\text {Area = Length x Length}}}

Given that the area is 144 unit²:

\text {Length}^2 = 144

\text {Length} = \sqrt{144} = 12 \text { units}

Formula for Perimeter of a square:

\boxed {\boxed {\text {Perimeter = 4 x Length }}}

\text {Perimeter = } 4 \times 12 = 48 \text { units}


\boxed { \boxed { \text {Answer: The perimeter is 48 units.}}}


6 0
3 years ago
The longer leg of a right triangle is 4 more than the short leg. The hypotenuse is eight less than the sum of the 2 legs.
Crazy boy [7]

Answer:

SteLet a = short leg of the right triangle, b = the longer leg, and c = the hypotenuse.

The longer leg of a right triangle is 4inches longer than the shorter leg: b = a + 4

The hypotenuse is 8inches longer than the shorter leg:  c = a + 8

 

Use the Pythagorean Theorem:

 

a2 + b2 = c2

a2 + (a+4)2 = (a+8)2

a2 + a2 + 8a + 16 = a2 + 16a + 64

a2 - 8a - 48 = 0

 

Factors to:

 

(a-12)(a+4) = 0

a = 12, -4

 

Since we can't have a side of -4, a = 12

Shorter Leg = 12 inches

Longer Leg = 12 + 4 = 16 inches

Hypotenuse = 12 + 8 = 20 inches

6 0
3 years ago
What is -3/11 divided by -5/6
Masja [62]

Answer:

0.00909090909

Step-by-step explanation:

8 0
3 years ago
Given an acceleration vector, initial velocity u0,v0,w0 , and initial position x0,y0,z0 , find the velocity and position vectors
dsp73

Answer:

Thus we find that velocity vector at time t is

(5t+15, 5t^2/2, 4t^2)

Step-by-step explanation:

given that acceleration vector is a funciton of time and at time t

a(t) = (5,5t, 8t)

v(t) can be obtained by integrating a(t)

v(t) = (5t, 5t^2/2, 4t^2)+(u_0,v_0,w_0)\\=(5t+15, 5t^2/2, 4t^2)

Thus we use the fact that acceleration is derivative of velocity and velocity is antiderivative of acceleration.

The arbitary constant normally used for integration C is here C vector = initial velocity (u0,v0,w0)

Position vector can be obtained by integrating v(t)

Thus we find that velocity vector at time t is

(5t+15, 5t^2/2, 4t^2)

5 0
3 years ago
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