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2 years ago

14

Someone please help me

1 answer:

kifflom [539]2 years ago

6 0

It's 4 ways 'cause u can travel by car, boat, train, and plane

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Mrs. Kennedy is buying pencils for each of 315 students. The pencils are sold in boxed of tens. How can she use rounding to deci

ExtremeBDS [4]

Mrs.Kennedy can divide 315 by 10 and then when she gets her answer she can round up to get her answer.

3 0

2 years ago

Is 1 1/4 a rational number?

lisabon 2012 [21]

Answer:

Hey there!

1 1/4 is a rational number because it can be expressed as a fraction.

Let me know if this helps :)

3 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bg%7D%7B3%7D%20%20%2B%207%20%3D%2019" id="TexFormula1" title=" \frac{g}{3} + 7 =

bonufazy [111]

Answer:

g = 36

Step-by-step explanation:

We have the equation $\frac{g}{3}$ + 7 =19

Subtract 7 from both sides: $\frac{g}{3}$ = 19 - 7 = 12

$\frac{g}{3}$ = 12

Now, multiply by 3 to both sides: 3 × $\frac{g}{3}$ = 3 × 12

g = 36

4 0

2 years ago

Read 2 more answers

Can SOMEBODYYY please do the maths!!! PLeassssssssssssseeeeeeee

Anna11 [10]

Answer:

<h2>see below</h2>

Step-by-step explanation:

<h3>Question-6:</h3>

we are given a equation

$\sf \displaystyle \: \log_{4}( - x) + \log_{4}( 6 - x) = 2$

to solve so

recall logarithm multiplication law:

$\sf \displaystyle \: \log_{4}( - x \times (6 - x)) = 2$

simplify multiplication:

$\sf \displaystyle \: \log_{4}( - 6 x + {x}^{2} ) = 2$

remember $\displaystyle \log_{4}(4^2)=2$

so

$\sf \displaystyle \: \log_{4}( - 6 x + {x}^{2} ) = \log_{4}( {4}^{2} )$

cancel out $\log_4$ from both sides:

$\sf \displaystyle \: - 6 x + {x}^{2} = {4}^{2}$

simplify squares:

$\sf \displaystyle \: - 6 x + {x}^{2} = 16$

move left hand side expression to right hand side and change its sign:

since we are moving left hand side expression to right hand side there'll be only 0 left in the left hand side

$\sf \displaystyle \: - 6 x + {x}^{2} - 16 = 0$

rewrite it to standard form i.e ax²+bx+c=0

$\sf \displaystyle \: {x}^{2} - 6x - 16 = 0$

rewrite -6x as 2x-8x:

$\sf \displaystyle \: {x}^{2} + 2x - 8x - 16 = 0$

factor out x and 8:

$\sf \displaystyle \: x {(x}^{} + 2) - 8(x + 2) = 0$

group:

$\sf \displaystyle \: (x - 8){(x}^{} + 2) = 0$

$\displaystyle \: x = 8 \\ x = - 2$

$\therefore \: x = - 2$

<h3>Question-7:</h3>

move left hand side log to right hand side:

$\displaystyle \: \log(x ) + \log(x - 21) = 2$

use mutilation logarithm rule;

$\displaystyle \: \log( {x}^{2} - 21x) = 2$

$\log(10^2)=2$ so

$\displaystyle \: \log( {x}^{2} - 21x) = \log({10}^{2} )$

cancel out log from both sides:

$\displaystyle \: {x}^{2} - 21x = 100$

make it standard form:

$\displaystyle \: {x}^{2} - 21x - 100= 0$

factor:

$\displaystyle \: {(x} + 4)(x - 25)= 0$

so

$\displaystyle \: x = 25$

5 0

2 years ago

SOMEONE PLEASE HELP ME WITH THIS ILL GIVE YOU BRAINLY IF YOU GET IT RIGHT PLEASE !!!!

lana [24]

Show me the first parts of the question

5 0

2 years ago