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2 years ago

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Mathematics

2 answers:

liraira [26]2 years ago

6 0

Answer:

8x-16y

Step-by-step explanation:

b.6a/6+18b/6-12c/6

Blababa [14]2 years ago

6 0

Answer:

8x - 16y and a + 3b - 2c

Step-by-step explanation:

(a)

8(x - 2y) ← multiply each term in the parenthesis by 8

= 8x - 16y

(b)

$\frac{6a+18b-12c}{6}$ ← factor out 6 from each term in the numerator

= $\frac{6(a+3b-2c)}{6}$ ← cancel the 6 on numerator/ denominator

= a + 3b - 2c

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Let II be the tangent plane to the graph of f(x, y) = 8 – 2x^2 – 3y^2 at the point (1, 2,-6). Let S, x² + y^2 + z = 4 be another

stealth61 [152]

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We have

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so the point we're looking for is (2, 6, -36).

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