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vampirchik [111]
2 years ago
10

A ski hill is angled 20° above the horizontal. If a skier starts from rest at the top of the hill, how fast will she be travelin

g after she has traveled 62 m 62 ⁢ m down the slope? Assume that friction is negligible.
Physics
1 answer:
MaRussiya [10]2 years ago
6 0

Answer:

20 m/s

Explanation:

First, we calculate for the acceleration down the incline using a = gsin\theta.

a = (9.80)sin(20°)

a = 3.35

Then, we use one of the kinematics equations, {v_{f}}^{2} = {v_{i}}^{2} + 2 a\Delta s.

v_{i} = 0 m/s

a = 3.35

\Delta s = 62 m

v_{f} = \sqrt{2(3.35)(62)}

v_{f} =20.381 = 20 m/s

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