Answer:
386 m
Explanation:
Let's call the horizontal distance between the point of launch and the point of landing of the first package
.
2 seconds after landing at
, the plane has travelled a horizontal distance of
.
At this new point, the second package is launched. Because it is launched under the same conditions as the first, its horizontal distance from its point of launch is also
.
To determine
, we determine the time of fall of the package. Being a vertical motion, the drop has an initial velocity,
, of 0 m/s with acceleration,
, and a distance,
, of 160 m. We use the equation of motion:



In this time, the package, with a horizontal velocity of 50 m/s, travels the horizontal distance,
, of

The distance apart between both packages is 