Here's one easy way:
-- Hang an object from a scale. Write down its weight in air.
-- Keep the object hanging from the scale, but let it down into water,
or whatever fluid you're interested in.
-- Read the scale again. Write down its weight in the fluid.
-- Dry everything off, clean up the lab, and go to your office with your notebook.
-- In your notebook, turn to the page with that day's observations.
Notice that the object's weight in air was greater than its weight in the fluid.
-- Subtract the weight in fluid from the weight in air.
The difference is the buoyant force on the object when it's in the fluid.
<span>Our verbal and nonverbal (LANGUAGE) provides clues to our attitude on a given topic.</span>
Answer:
a) 1511 MW
b) 44%
Explanation:
The thermal power will be the electric power plus the heat taken away by the cooling water.
Qt = P + Qc
The heat taken away by the water will be:
Qc = G * Cp * (t1 - t0)
The Cp of water is 4180 J/(kg K)
The density of water is 1 kg/L
Then
G = 1.17 * 10^8 L/h * 1 kg/L * 1/3600 h/s = 32500 kg/s
Now we calculate Qc
Qc = 32500 * 4180 * (29.8 - 23.6) = 842*10^6 W = 842 MW
The total thermal power then is
Qt = 669 + 842 = 1511 MW
The efficiency is
η = P / Qt
η = 669 / 1511 = 44%
The time for the javelin in the air will be 3.977 second
<h3>What is the period?</h3>
The value of time needed to complete the upward and the downward motion is the total period. Its unit is the second and is denoted by t. T is the time at which the ball first hits the ground.
Given data;
Θ is the angle of throw = 43.2°
u is the thrown velocity = 28.5 m/s
t is the time for the javelin in the air
The time period is found as;
Hence the time for the javelin in the air will be 3.977 second
To learn more about the period, refer to the link;
brainly.com/question/569003
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