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3 years ago

How does mineral growth occur?

Physics

2 answers:

sukhopar [10]3 years ago

6 0

Atoms are added to crystal faces
hope this helps :)

marissa [1.9K]3 years ago

3 0

Atoms are added to crystal faces.

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If mass of both the objects are doubled

Fofino [41]

Answer:

it should be four times

4 0

2 years ago

Jill applies a force of 15 N to a wrench. If

Ivenika [448]

Jill is the input, as she creates the force. The wrench is the output because it gives the force to the finish peace of the chain.

6 0

3 years ago

The y-position of a damped oscillator as a function of time is shown in the figure.

NISA [10]

(1) The period of the oscillator is 1 second.

(2) The damping coefficient is 0.93.

<h3>What is period of oscillation?</h3>

The period of oscillation is the time taken to make one complete cycle.

From the graph, the time taken to make one complete oscillation is 1 second.

<h3>Damping coefficient</h3>

equation of the wave is given as;

y(t) = Ae^(-btx) cos(ωt)

3.5 = Ae^(-0) cos(0)

3.5 = A x 1

A = 3.5 cm

-3 = 3.5e^(-bx) cos(ω)

-3/3.5 = e^(-bx) cos(ω)

-0.857 = e^(-bx) cos(ω)

-0.857 / cos(ω) = e^(-bx)

ln[-0.857 / cos(ω)] = -bx

ln[-0.857 / cos(ω)] / b = - x ---- (1)

-2 = 3.5e^(-2bx) cos(2ω)

-0.57 = e^(-2bx) cos(2ω)

ln[-0.57 / cos(2ω)] = -2bx

ln[-0.57 / cos(2ω)] /2b = - x ------(2)

solve (1) and (2)

ln[-0.57 / cos(2ω)]/2b = ln[-0.857 / cos(ω)] /b

-0.57 / cos(ω) = 2(-0.857 / cos(ω))

2(-0.857/cosω) = -0.57/cos2ω

-(2 x 0.857) / (-0.57) = cosω/cos 2ω

3 = cosω/cos 2ω

3(cos 2ω) = cosω

3(2cos²ω - 1) = cos ω

6cos²ω - 6 = cosω

6cos²ω - cosω - 6 = 0

let cosω = y

6y² - y - 6 = 0

solve the quadratic equation;

y = 1.1 or -0.92

cosω = -0.92

ω = arc cos(-0.92)

ω = 2.74 rad/s

From equation (1)

ln[-0.857 / cos(ω)] / x = -b ---- (1)

let x = 1

ln(-0.857/cos(2.74) = -b

-0.93 = -b

b = 0.93

Thus, the damping coefficient is 0.93.

Learn more about damping coefficient here: brainly.com/question/14058210

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4 0

2 years ago

A large meteoroid enters the Earth's atmosphere at a speed of 20.0 km/s and is not significantly slowed before entering the ocea

Shalnov [3]

The shock wave from the meteoroid in the lower atmosphere has a Mach angle of 0.948°.

(a) The meteoroid's speed $v_s=20 \mathrm{~km} / \mathrm{s}$

$=20 \times 10^3 \mathrm{~m} / \mathrm{s}$

Air sound wave speed $&v=331 \mathrm{~m} / \mathrm{s} \\$

Speed of the shock wave in Mach $&\qquad \theta=\sin ^{-1}\left(\frac{v}{v_s}\right)$

$\begin{aligned}&=\sin ^{-1}\left(\frac{331 \mathrm{~m} / \mathrm{s}}{20 \times 10^3 \mathrm{~m} / \mathrm{s}}\right) \\&=0.948^{\circ}\end{aligned}$

Hence, 0.948° is the Mach angle of the shock wave from the meteoroid in the lower atmosphere.

<h3>What is the speed of the meteoroid?</h3>

A meteoroid's speed can be loosely broken down into three categories: slow, medium, and fast.

Slow meteors move around the sun at a leisurely pace of about 32 kilometers per second (20 miles per second).
Medium-speed meteors travel around the sun at approximately 50 kilometers per second (30 miles per second),
while fast meteors zoom past at over 120 kilometers per second (75 miles per second)!

To learn more about meteoroid, visit:

brainly.com/question/1939309

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5 0

1 year ago

What are the three factors needed for Newton’s Second Law?

Anastasy [175]

Answer:

the weight of the object, the force of gravity acting on said object, and the mass of the object are needed for Newton's second law of motion.

5 0

3 years ago