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3 years ago

If a shirt selling for $18 is marked upto $20 then the % increase is

Mathematics

2 answers:

luda_lava [24]3 years ago

8 0

Answer:

11%

Step-by-step explanation:

it is a simple question, whenever you need to find % increase or % decrease.

always divide the increase as in this case $2 by the original amount which is $18 and multiply it by 100 as you need to take the %.

so,

2/18*100 gives you 11.11% * is multiply

const2013 [10]3 years ago

6 0

Step-by-step explanation:

$20 - $18 = $2

to get % of increase we need to know what % of $18 the $2 are.

$2 ÷ $18 = 0.11111111........

Multiply this number by 100 and you will get the percentage.

0.111111111111........ x 100 = 11.1111111111....%

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3 years ago

Brian recorded the number of commercials played during two types of television shows: an educational documentary and a primetime

Sladkaya [172]

Answer:

$m(x)_A = 5.2$ --- Mean absolute deviation of educational documentary

$m(x)_B = 4.7$ --- Mean absolute deviation of prime time drama

Step-by-step explanation:

Given

$n = 10$

See attachment for table

Required

Determine the mean absolute deviation of each

Mean absolute deviation m(x) is calculated as:

$m(x) = \frac{1}{n}\sum |x - \mu|$

For Educational Documentary

First, calculate the mean

$\mu = \frac{\sum x}{n}$

So:

$\mu_A = \frac{26 + 28 + 30 + 18+27 + 18 + 20 +31+17+17}{10}$

$\mu_A = \frac{232}{10}$

$\mu_A = 23.2$

The mean absolute deviation is then calculated as:

$m(x)_A = \frac{1}{n}\sum |x - \mu_A|$

$m(x)_A = \frac{1}{10}(|26 -23.2| +|28 -23.2| +|30 -23.2| +|18 -23.2| +|27 -23.2| +|18 -23.2| +|20 -23.2| +|31 -23.2| +|17 -23.2| +|17 -23.2|)$

$m(x)_A = \frac{1}{10}(|2.8| +|4.8| +|6.8| +|-5.2| +|3.8| +|-5.2| +|-3.2| +|7.8| +|-6.2| +|-6.2|)$

$m(x)_A = \frac{1}{10}(2.8 +4.8 +6.8 +5.2 +3.8 +5.2 +3.2 +7.8 +6.2 +6.2)$

$m(x)_A = \frac{1}{10}*52$

$m(x)_A = 5.2$

For Prime time Drama

First, calculate the mean

$\mu = \frac{\sum x}{n}$

So:

$\mu_B = \frac{39+39+35+29+40+27+41+29+32+30}{10}$

$\mu_B = \frac{341}{10}$

$\mu_B = 34.1$

The mean absolute deviation is then calculated as:

$m(x)_B = \frac{1}{n}\sum |x - \mu_B|$

$m(x)_B = \frac{1}{10}(|39-34.1|+|39-34.1|+|35-34.1|+|29-34.1|+|40-34.1|+|27-34.1|+|41-34.1|+|29-34.1|+|32-34.1|+|30-34.1|)$

$m(x)_B = \frac{1}{10}(|4.9|+|4.9|+|0.9|+|-5.1|+|5.9|+|-7.1|+|6.9|+|-5.1|+|-2.1|+|-4.1|)$

$m(x)_B = \frac{1}{10}(4.9+4.9+0.9+5.1+5.9+7.1+6.9+5.1+2.1+4.1)$

$m(x)_B = \frac{1}{10}*47$

$m(x)_B = 4.7$

6 0

3 years ago

In mathematics given that x=L2-L1/L1(O2-O1).

Assoli18 [71]

Answer:

1. L1 = $\frac{L2}{X(O2 -O1)}$

2. O2 = $\frac{L2 - L1(1 + XO1)}{XL1}$

Step-by-step explanation:

Given: x = $\frac{L2 - L1}{L1(O2 -O1)}$

1. To make L1 the subject of formula;

x = $\frac{L2 - L1}{L1(O2 -O1)}$

cross multiply to have;

L2 - L1 = xL1(O2 - O1)

collect like terms,

L2 = xL1(O2 - O1) + L1

factorize the right hand side;

L2 = L1[x(O2 - O1)]

L1 = $\frac{L2}{X(O2 -O1)}$

2. To make O2 the subject of formula;

x = $\frac{L2 - L1}{L1(O2 -O1)}$

cross multiply to have;

L2 - L1 = xL1(O2 - O1)

open the bracket to have;

L2 - L1 = xL1O2 - xL1O1

⇒ xL1O2 = L2 - L1 + xL1O1

O2 = $\frac{L2-L1 + XL1O1}{XL1}$

= $\frac{L2 - L1(1 + XO1)}{XL1}$

4 0

3 years ago