The further left a number is the less it is
The further right a number is the greater it is
Answer:
2
Step-by-step explanation:
You can rewrite thosee two equations as -9x+12=-6, because f(x)=f(x)
Now isolate x
-9x+12=-6
-9x+12-12=-6-12 (subtract 12, subtraction property of equality)
-9x=-6-12
-9x=-18 (simplify)
-9x/-9=-18/-9 (divide by 9, division property of equality)
x=2
Volume of a ball = (4/3)πr³
When r = 18cm, V = (4/3)×3.14×18³ =24416.64 cm³
When r = 12cm, V = (4/3)×3.14×12³ =7234.56 cm³
Difference = 24416.64 - 7234.56 = 17182.08 cm³
the volume of air in the larger ball is <span>17182.08 cm³ greater than smaller ball </span>
Let p be
the population proportion. <span>
We have p=0.60, n=200 and we are asked to find
P(^p<0.58). </span>
The thumb of the rule is since n*p = 200*0.60
and n*(1-p)= 200*(1-0.60) = 80 are both at least greater than 5, then n is
considered to be large and hence the sampling distribution of sample
proportion-^p will follow the z standard normal distribution. Hence this
sampling distribution will have the mean of all sample proportions- U^p = p =
0.60 and the standard deviation of all sample proportions- δ^p = √[p*(1-p)/n] =
√[0.60*(1-0.60)/200] = √0.0012.
So, the probability that the sample proportion
is less than 0.58
= P(^p<0.58)
= P{[(^p-U^p)/√[p*(1-p)/n]<[(0.58-0.60)/√0...
= P(z<-0.58)
= P(z<0) - P(-0.58<z<0)
= 0.5 - 0.2190
= 0.281
<span>So, there is 0.281 or 28.1% probability that the
sample proportion is less than 0.58. </span>
The wording of this question is a bit confusing... You can't write a sequence in sigma notation, but rather a series or sum. I think the question is asking you to write the sum of the sequence,
which would be
in sigma notation.
To do this, notice that the denominator in each term is a power of 2, starting with 
and ending with 
. So in sigma notation, this series is
