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iVinArrow [24]
2 years ago
5

The average temperature of the atmosphere in the world is approximated as a function of altitude by the relation Tatm=288.15−6.5

z where Tatm is the temperature of the atmosphere in K, and z is the altitude in km with z = 0 at sea level. Determine the average temperature of the atmosphere outside an airplane that is cruising at an altitude of 12600 m. The average temperature of the atmosphere outside an airplane is
Mathematics
1 answer:
Yuri [45]2 years ago
3 0

Answer:

The average temperature of the atmosphere outside the airplane is 206.25\,K.

Step-by-step explanation:

The average temperature of the atmosphere outside an airplane flying at an altitude of 12600 meters is computed by evaluating the linear function:

T (12.6\,km) = 288.15 - 6.5\cdot (12.6\,km)

T (12.6\,km) = 206.25\,K

The average temperature of the atmosphere outside the airplane is 206.25\,K.

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Enter your answer and show all the steps that you use to solve this problem in the space provided. Find the values of x and y.
satela [25.4K]

Answer : The value of x and y is, 90^o and 43^oC

Step-by-step explanation :

First we have to calculate the angle B.

As we know that,

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What is x-2y=-1 and 2x+y=4 using elimination step by step
otez555 [7]

Answer:

x = 7/5  , y = 6/5

Step-by-step explanation using elimination:

Solve the following system:

{x - 2 y = -1 | (equation 1)

2 x + y = 4 | (equation 2)

Swap equation 1 with equation 2:

{2 x + y = 4 | (equation 1)

x - 2 y = -1 | (equation 2)

Subtract 1/2 × (equation 1) from equation 2:

{2 x + y = 4 | (equation 1)

0 x - (5 y)/2 = -3 | (equation 2)

Multiply equation 2 by -2:

{2 x + y = 4 | (equation 1)

0 x+5 y = 6 | (equation 2)

Divide equation 2 by 5:

{2 x + y = 4 | (equation 1)

0 x+y = 6/5 | (equation 2)

Subtract equation 2 from equation 1:

{2 x+0 y = 14/5 | (equation 1)

0 x+y = 6/5 | (equation 2)

Divide equation 1 by 2:

{x+0 y = 7/5 | (equation 1)

0 x+y = 6/5 | (equation 2)

Collect results:

Answer: {x = 7/5  , y = 6/5

5 0
3 years ago
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