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zysi [14]
3 years ago
14

A runner runs the first 400m of a race in 80s, the second 400m in 70s and the final 800m in 130s. What was her average speed for

this run?
Physics
1 answer:
-BARSIC- [3]3 years ago
5 0

Answer: The average speed is 5.71 m/s

Explanation:

The average speed in this run will be the quotient between the total distance that the runner traveled, and the total time it took.

Distance = 400m + 400m + 800m = 1600m

Time = 80s + 70s + 130s = 280s

Then the average speed is:

S = 1600m/280s = 5.71 m/s

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After flying for 15 min in a wind blowing 42 km/h at an angle of 19° south of east, an airplane pilot is over a town that is 48
masha68 [24]

Answer:

The speed of the airplane relative to the air is 209.47km/hr

Explanation:

Whenever we are solving a physics problem, it's really useful to start by drawing a diagram of the problem (See picture attached). It will help us visualize the problem better.

Now, we know that the plane flew for an amount of time of 15 minutes. For our dimensions to be the same, we need to turn those 15min to hours, like this:

15min*\frac{1hr}{60min}=0.25hr

Once our time is rewritten as hours, we can now calculate the velocity towards north of the plane.

V=\frac{distance}{time}

the plane traveled a distance to the north of 48km so the velocity is:

V=\frac{48km}{0.25hr}

so

V=192km/hr j

Now, we can calculate the x and y-components of the velocity of the wind. The problem states that the wind is blowing at 42km/hr at an angle of 19° south of east, so the x and y-components of the velocity of the wind are:

V_{x}=42km/hr*cos(-19^{o} )=39.71 i

and

V_{y}=42km/hr*sin(-19^{o} )=-13.67 j

So the velocity of the wind can be expressed as a vector as:

V_{wind}=(39.71i - 13.67j)km/hr

Once we know this, we can find the velocity of the plane with respect of the wind on x and on y:

V_{plane x}=V_{plane/wind x}+V_{wind x}

V_{plane/wind x}=V_{plane x}-V_{wind x}

V_{plane/wind x}=(0-39.71 i)km/hr

V_{plane/wind x}= -39.71 i km/hr

and

V_{plane y}=V_{plane/wind y}+V_{wind y}

V_{plane/wind y}=V_{plane y}-V_{wind y}

V_{plane/wind y}=192km/hr j - (- 13.67j)km/hr

V_{plane/wind x}= 205.67 j km/hr

So the velocity of the plane with respect to the wind can be rewritten as:

V_{plane/wind x}= (-39.71i + 205.67 j) km/hr

Since the problem asks us to find the speed of the plane with respect to the wind, this means that we need to find the magnitude of the velocity, since the speed is a scalar defined to be the magnitude of the velocity.

so:

speed=\sqrt{(-39.71)^{2}+(205.67)^{2}  }

speed= 209.47 km/hr

Therefore, the speed of the airplane relative to the air is 209.47km/hr

6 0
3 years ago
Wich type of mutation occurs in reproductive cell and can be passed to offspring? A sommatic mutation B germline mutation C poin
ryzh [129]

The answer to your question is,

B. Germline mutation

-Mabel <3

7 0
3 years ago
b) Assume the rod is 0.60 m long and has a mass of 0.50 kg, and the clay blob has a mass of 0.20 kg and moves at an initial velo
SOVA2 [1]

Answer:

The correct answer is "6.96 rad/s".

Explanation:

The given values are:

Length,

L = 0.6 m

Mass,

m₁ = 0.5 kg

m₂ = 0.2 kg

Initial velocity,

V = 8 m/s

Now,

The final angular velocity will be:

⇒ \omega =\frac{6m_1V}{(4m_1+3m_2)L}

By substituting the values, we get

⇒     =\frac{6\times 0.2\times 8}{(4\times 0.2+3\times 0.5)0.6}

⇒     =\frac{9.6}{1.38}

⇒     =6.96 \ rad/s

4 0
3 years ago
If momentum is conserved, what happened to velocity when mass changes?
kifflom [539]

Explanation:

The momentum of an object is given in terms of its mass and its velocity. The law of conservation of momentum says that the net momentum of a system remains conserved for an isolated system.

Momentum is given by :

p = m × v

If p is conserved, velocity is inversely proportional to the mass of an object. When mass changes, velocity also changes but inversely.

5 0
3 years ago
According to missouri law, during what hours is it legal for a boat to tow a water-skier?
Tomtit [17]
<span>According to missouri law, it is legal for a boat to tow a water-skier from sunrise to sunset. Water skis, wakeboard and parasailing are allowed from sunrise to sunset. These can be performed by towing the person from behind a motorboat or PWC. A reasonable distance should be maintained between vessels, properties and people to avoid any accidents. It is illegal for an intoxicated person to ride the vessel.</span>
6 0
3 years ago
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