The vertical component of the velocity after the given time is -9.8 m/s while the horizontal component of the velocity is 16 m/s.
The given parameters;
- initial horizontal velocity, vₓ = 16 m/s
- initial vertical velocity,
- time interval 1 seconds
The components of the velocity can be horizontal or vertical velocity.
The vertical component of the velocity is affected by acceleration due to gravity while the horizontal component of the velocity is not affected by gravity.
The vertical component of the velocity is calculated as;
The horizontal component of the velocity is constant since it is not affected by gravity.
The horizontal component of the velocity = 16 m/s
Thus, the vertical component of the velocity after the given time is -9.8 m/s while the horizontal component of the velocity is 16 m/s.
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According to Newton second law of motion, the resultant force is directly proportional to the rate of change in momentum while maintaining other factors constant. Therefore, F = (mv-mu)/t where F is the resultant force , m is the mass of the object, v is the final velocity and u is the initial velocity.
Hence, Ft = mv-mu, but impulse is given by force multiplied by time, thus, impulse is equivalent to the change in momentum.
Impulse = Ft
= 325 × 2.2 sec
= 715 Ns
Force and Gravity, is what i think it is.
1449 is the answer to the question
Answer:
0.6 μC
Explanation:
C = capacitance of the capacitor = 100 x 10⁻¹² F
d = separation between the plates of capacitor = 1 mm = 1 x 10⁻³ m
E = Electric field = 6 x 10⁶ N/C
Q = Amount of charge
V = Potential difference
Potential difference is given as
V = E d
Amount of charge stored is given as
Q = CV
hence
Q = C E d
inserting the values
Q = (100 x 10⁻¹²) (6 x 10⁶) (1 x 10⁻³)
Q = 6 x 10⁻⁷ C
Q = 0.6 μC
