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Bingel [31]
3 years ago
13

A bumblebee is flying to the right when a breeze causes the bee to slow down with a constant leftward acceleration of magnitude

0.50\,\dfrac{\text m}{\text s^2}0.50 s 2 m ​ 0, point, 50, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction. After 2.0\,\text{s}2.0s2, point, 0, start text, s, end text, the bee is moving to the right with a speed of 2.75\,\dfrac{\text m}{\text s}2.75 s m ​ 2, point, 75, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction. What was the velocity of the bumblebee right before the breeze?
Physics
1 answer:
lesya692 [45]3 years ago
7 0

Answer:

3.75 m/s

Explanation:

Given:

v = 2.75 m/s

a = -0.50 m/s²

t = 2.0 s

Find: v₀

v = at + v₀

2.75 m/s = (-0.50 m/s²) (2.0 s) + v₀

v₀ = 3.75 m/s

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A tightly wound 1000-turn toroid has an inner radius 1.00 cm and an outer radius 2.00 cm, and carries a current of 1.50 A. The t
V125BC [204]

Therefore, the magnitude of magnetic field at a distance 1.10cm from the origin is 27.3mT

<u>Explanation:</u>

Given;

Number of turns, N = 1000

Inner radius, r₁ = 1cm

Outer radius, r₂ = 2cm

Current, I = 1.5A

Magnetic field strength, B = ?

The magnetic field inside a tightly wound toroid is given by B = μ₀ NI / 2πr

where,

a < r < b and a and b are the inner and outer radii of the toroid.

The magnetic field of toroid is

B = \frac{u_oNI}{2\pi r}

Substituting the values in the formula:

B (1.10cm) = \frac{(4\pi X 10^-^7 ) ( 1000)(1.5)}{2\pi (1.10) } \\\\

B (1.10cm) = 27.3mT

Therefore, the magnitude of magnetic field at a distance 1.10cm from the origin is 27.3mT

7 0
3 years ago
If the cross-section of a wire of fixed length is doubled, how does the resistance of that wire change? A. Halved. B. Doubled C.
Vinil7 [7]
(B)It would get doubled.
7 0
3 years ago
The height of the Washington Monument is measured to be 170 m on a day when its temperature is 35.0°C. What will the change in i
Alecsey [184]

Answer:

The deformation is 0.088289 m

The final height of the monument is 170-0.088289 = 169.911702 m

Explanation:

Thermal coefficient of marble varies between (5.5 - 14.1) ×10⁻⁶/K = α

So, let us take the average value

(5.5+14.1)/2 = 9.8×10⁻⁶ /K

Change in temperature = 35-(-18) = 53 K = ΔT

Original length = 170 m = L

Linear thermal expansion

\frac{\Delta L}{L} = \alpha\Delta T\\\Rightarrow \Delta L=\frac{\alpha\Delta T}{L}\\\Rightarrow \Delta L=9.8\times 10^{-6}\times 53\times 170

The deformation is 0.088289 m

The final height of the monument is 170-0.088289 = 169.911702 m (subtraction because of cooling)

4 0
3 years ago
Two piano strings produce beats. Frequencies of the strings are 1560 Hz. and 1563 Hz. Choose the correct frequency of the beats.
kakasveta [241]

Beat frequency is given by the difference of two frequencies played together

f_{beat} = |f_1 - f_2|

given that

f_1 = 1560 Hz

f_2 = 1563 Hz

Now

f_{beat} = |1560- 1563| Hz

f_{beat} = 3 Hz

3 0
3 years ago
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(2)<span>less than 750 N.( if the downward acceleration of elevator were g,then answer would be 0 N.)</span>
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