3-i/2
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Notice that
11/12 = 1/6 + 3/4
so that
tan(11π/12) = tan(π/6 + 3π/4)
Then recalling that
sin(x + y) = sin(x) cos(y) + cos(x) sin(y)
cos(x + y) = cos(x) cos(y) - sin(x) sin(y)
⇒ tan(x + y) = (tan(x) + tan(y))/(1 - tan(x) tan(y))
it follows that
tan(11π/12) = (tan(π/6) + tan(3π/4))/(1 - tan(π/6) tan(3π/4))
tan(11π/12) = (1/√3 - 1)/(1 + 1/√3)
tan(11π/12) = (1 - √3)/(√3 + 1)
tan(11π/12) = - (√3 - 1)²/((√3 + 1) (√3 - 1))
tan(11π/12) = - (4 - 2√3)/2
tan(11π/12) = - (2 - √3) … … … [A]
Answer:
Step-by-step explanation:
From the graph <em>f</em>(-2) = 0
g(-2) = -3(-2) + 2
= 6 + 2 = 8.
So f(-2) is less than g(-2).
2. From the graph the y-intercept of f(x) = 8.
To find the y-intercept of g(x) solve y = -3x +2 when x = 0:
y = -3(0) + 2 = 2.
So f(x) has a greater y-intercept than g().
Answer:
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Step-by-step explanation:
