Answer:
1. G=D+(A+C^2)*E/(D+B)^3
cobegin:
p1: (D+B)
p2: p1^3
p3: C^2
p4: A+ p3
p5: E/p2
p6: p4 * p5
p7: D + p6
:G
coend
2. Now The value A=2, B=4, C=5, D=6, and E=8
p1: 6+4 =10
p2: p1 ^3= 10^3= 1000
p3: c^2= 5^2 =25
p4: A + p3= 2 +25 =27
p5: 8/1000
p6: 27 *8/1000
p7: D+ P6= 6+ 216/1000
= 6216/1000
=6.216
Explanation:
The above, first bracket with power is processed, and then power inside and outside bracket. And rest is according to BODMAS, and one process is solved at a time.
Answer:
(A) The CPU time for J1 is =2 ms other time is =18 ms, for J2 CPU time =6 ms other time = 24 ms, for J3 CPU time = 3 ms and other time = 12 ms (B) The CPU Utilization for uni-programming is 0.203 or 20.3% (C) For Multi-programming, when a program is not free and busy with an operation, the CPU is allocated to other programs.
Explanation:
Solution
Given that:
A(1)Job J1 = CPU time = 2ms
Other time =18 ms
Total time = 20 ms
(2)Job J2 = CPU time 6ms
Other time = 24 ms
Total time = 30 ms
(3)Job J3 = CPU time = 3ms
Other time =12ms
Total time = 15 ms
(B) For the CPU Utilization for uni-programming, we have the following as follows:
CPU utilization =The total time of CPU/The total real time
Thus,
=(2 +6+3) / (18+24+12)
= 11/54
=0.203 or 20.3%
(C) For the CPU utilization for multi-programming, when a program is not available that is busy in an operation, such as the input and output the CPU can be allocated or designated to other programs
Answer:
2
Explanation:
User submit quantity 2. with Color : Red Blue Green
Answer:
C. Blinking vertical line on your screen
Explanation:
A cursor is tha blinking vertical line on your screen.
