Slayyy queeen slayyy

Given an array temps of double s, containing temperature data, compute the average temperature. Store the average in a variable

Ket [755]

Answer:

#include <iostream>

using namespace std;

// average function

void average(double arr[], int n) {

double total = 0;

double avgTemp;

for (int i = 0; i < n; i++)

{

// find temperatures total

total = total + arr[i];

}

// find average

avgTemp = total / n;

cout << "\nAverage Temperature = " << avgTemp << endl;

}

// print temps[] array

void printArray(double arr[], int n) {

for (int i = 0; i < n; i++)

{

cout << arr[i] << " ";

}

int main() {

int const k = 5;

double temps[k];

// temperature value

double tempValue;

// Enter 5 temperatures of your choice

for (int i = 0; i < k; i++)

{

cout << "Enter Temperature value " << i+1 << ": ";

cin >> tempValue;

temps[i] = tempValue;

}

// Function call to print temps[] array

printArray(temps, k);

// Function call to print average of given teperatures

average(temps, k);

return 0;

}

Explanation:

• Inside main(), int constant k is created to set the maximum size of array temps[].

• tempValue of type double takes value at a given index of our temps[] array.

• the for loop inside main() is used to get tempValue from the user and store those values in our array temps[].

• after that printArray() function is called. to pass an array to a function it requires to perimeters 1) name of the array which is temps in our case. 2) maximum number of the index which is k.

• note the syntax of void average(double arr[], int n). Since we are passing an array to the function so its formal parameters would be arr[] and an int n which specifies the maximum size of our array temps[].

6 0

3 years ago

We have said that the average number of comparisons need to find a target value in an n-element list using sequential search is

bija089 [108]

Answer:

Part a: If the list contains n elements (where n is odd) the middle term is at index (n-1)/2 and the number of comparisons are (n+1)/2.

Part b: If the list contains n elements (where n is even) the middle terms are at index (n-2)/2 & n/2 and the number of comparisons are (n+2)/2.

Part c: The average number of comparisons for a list bearing n elements is 2n+3/4 comparisons.

Explanation:

Suppose the list is such that the starting index is 0.

Part a

If list has 15 elements, the middle item would be given at 7th index i.e.

there are 7 indices(0,1,2,3,4,5,6) below it and 7 indices(8,9,10,11,12,13,14) above it. It will have to run 8 comparisons to find the middle term.

If list has 17 elements, the middle item would be given at 8th index i.e.

there are 8 indices(0,1,2,3,4,5,6,7) below it and 8 indices(9,10,11,12,13,14,15,16) above it.It will have to run 9 comparisons to find the middle term.

If list has 21 elements, the middle item would be given at 10th index i.e.

there are 10 indices (0,1,2,3,4,5,6,7,8,9) below it and 10 indices (11,12,13,14,15,16,17,18,19,20) above it.It will have to run 11 comparisons to find the middle term.

Now this indicates that if the list contains n elements (where n is odd) the middle term is at index (n-1)/2 and the number of comparisons are (n+1)/2.

Part b

If list has 16 elements, there are two middle terms as one at would be at 7th index and the one at 8th index .There are 7 indices(0,1,2,3,4,5,6) below it and 7 indices(9,10,11,12,13,14,15) above it. It will have to run 9 comparisons to find the middle terms.

If list has 18 elements, there are two middle terms as one at would be at 8th index and the one at 9th index .There are 8 indices(0,1,2,3,4,5,6,7) below it and 8 indices(10,11,12,13,14,15,16,17) above it. It will have to run 10 comparisons to find the middle terms.

If list has 20 elements, there are two middle terms as one at would be at 9th index and the one at 10th index .There are 9 indices(0,1,2,3,4,5,6,7,8) below it and 9 indices(11,12,13,14,15,16,17,18,19) above it. It will have to run 11 comparisons to find the middle terms.

Now this indicates that if the list contains n elements (where n is even) the middle terms are at index (n-2)/2 & n/2 and the number of comparisons are (n+2)/2.

Part c

So the average number of comparisons is given as

((n+1)/2+(n+2)/2)/2=(2n+3)/4

So the average number of comparisons for a list bearing n elements is 2n+3/4 comparisons.

6 0

3 years ago

One of the most common causes of fires in the home and workplace is: a. All of the answer choices b. Arson c. Candle d. Faulty e

solniwko [45]

Electricity is one of the most common causes of fire in homes and workplaces. Electrical accidents appear to be caused by a combination of two factors: 1. Unsafe equipment and/or installation; 2. Workplaces made unsafe by the environment

So the answer would be D)Faulty electricity

8 0

3 years ago

Information that has been analyzed and refined so that it is useful to policymakers in making decisions; specifically, decisions

denis-greek [22]

Answer:

Intelligence

Explanation:

Intelligence is the product resulting from the collection, collation, evaluation, analysis, integration, and interpretation of collected information. It is a specialised information product that provides an adversary with information required to further its national interests. One of the most important functions of intelligence is the reduction of the ambiguity inherent in the observation of external activities.rations.

In most cases, the development of an intelligence product involves collecting information from a number of different sources. In some cases, information may be disseminated immediately upon collection based upon operational necessity and potential impact on current operations.

Strategic intelligence provides policy makers with the information needed to make national policy or decisions of long-lasting importance. Strategic intelligence collection often requires integrating information concerning politics, military affairs, economics, societal interactions, and technological developments. It typically evolves over a long period of time and results in the development of intelligence studies and estimates.

Operational intelligence is concerned with current or near-term events. It is used to determine the current and projected capability of a program or operation on an ongoing basis and does not result in long-term projections. Most intelligence activities support the development of operational intelligence.

8 0

3 years ago

Some hardware can be added to the computer without having to restart or power down the computer. After a short period of time th

faltersainse [42]

Answer:

Plug and play technology

Explanation:

Plug and play technology also know as PnP allows user to directly connect devices to a computer and start using inmediatly. Other way user must have to search and install drivers for each component.

Usually PnP comes for regular use devices like: Keyboards, mouses, flashmemories, cameras, and others

8 0

3 years ago