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nignag [31]
3 years ago
10

Solve for h in the mathematical formula A=1/2(a+b)h

Mathematics
1 answer:
AnnZ [28]3 years ago
8 0

Step-by-step explanation:

Since we arent given enough information to SOLVE for h, I will get as close as I can by rearranging the equation for h

Convert the fraction to a decimal for simplicity

A = 0.5(a + b)h

Divide both sides of the equals by 0.5

A/0.5 = (a + b)h

We can convert A/0.5 into its reciprocal

2 A = (a + b)h

Divide both sides of the equation by the bracketed (a + b)

(2 A)  /  (a + b) = h

Rewritten

<h2>h =  \frac{2A}{(a + b)}</h2>
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If abc+1=0, prove that: (1/1−a−b^-1)+(1/1−b−c^-1)+(1/1−c−a^−1​)=1​
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If A=1/2h(x+y), what is y in terms of A, h, and x?
lapo4ka [179]

Answer:

see explanation

Step-by-step explanation:

Given

A = \frac{1}{2} h(x + y)

Multiply both sides by 2 to eliminate the fraction

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A loan of $36,000 is made at 6.75% interest, compounded annually. After how many years will the amount due reach $57,000 or more
irakobra [83]

Answer:

After 7.04 years the amount will reach $57,000 or more

Step-by-step explanation:

The rule of the compound interest is A=P(1+\frac{r}{n})^{nt} , where

  • A is the new value
  • P is the initial value
  • r is the rate in decimal
  • n is the period of the time
  • t is the time

∵ A loan of $36,000 is made at 6.75% interest, compounded annually

∴ P = 36,000

∴ r = 6.75% = 6.75 ÷ 100 = 0.0675

∴ n = 1 ⇒ compounded annually

∵ The amount after t years will reach $57,000 or more

∴ A = 57,000

→ To find t substitute these values in the rule above

∵ 57,000 = 36,000 (1+\frac{0.0675}{1})^{(1)(t)}

∴ 57,000 = 36,000 (1.0675)^{t}

→ Divide both sides by 36,000

∵ \frac{19}{12} =  (1.0675)^{t}

→ Insert ㏒ in both sides

∴ ㏒( \frac{19}{12} ) = ㏒ (1.0675)^{t}

→ Remember ㏒a^{n} = n ㏒(a)

∵ ㏒( \frac{19}{12} ) = <em>t</em> ㏒(1.0675)

→ Divide both sides by ㏒(1.0675)

∴ 7.035151337 = <em>t</em>

<em>∴ </em><em>t </em>≅ 7.04

∴ After 7.04 years the amount will reach $57,000 or more

4 0
3 years ago
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