I just took the quiz, the answer is A: Critical values=0.312; there is sufficient evidence to support a claim of a linear correlation between before-and-after weights.
Let S=larger square side and s=smaller square side. The area between the larger and smaller is simple the larger area minus the smaller area. The area of any square being s^2. So our remaining area is:
A=S^2-s^2
A=144-49=95 cm^2
3 odd integers have a property that they average up to the middle large one. Let's say we have 3, 5, and 7. 3 is 2 less than 5 and 7 is 2 more than 5. so when you add them it equals 2 times 5.
After we know that, the sum of 3 odd integers is just 3 times the middle number. ex. 3+5+7 = 3 times 5 = 15
Then we know the some number times three = 225. we find out that the middle number is 75, so the other two are 73 and 77
Answer:
The points of the rotated shape are: (4, 1), (5, 3), (4, 4), (2, 1), (1, 3), (2, 4)
Step-by-step explanation:
From the part of the shape we can see and the symmetry, the missing points are:
(-2, -1)
(-1, -3)
(-2, -4)
Rotation 180° about the origin transforms the point (x, y) into (-x, -y). Applying this rule to our figure, we get:
(-4, -1) -> (4, 1)
(-5, -3) -> (5, 3)
(-4, -4) -> (4, 4)
(-2, -1) -> (2, 1)
(-1, -3) -> (1, 3)
(-2, -4) -> (2, 4)
Answer:
38.13 m^2
Step-by-step explanation:
the area of a triangle =b*h/2
b=base
h=height
area triangle=(4m*3m)/2=(12m^2)/2=6m^2
the area of a rectangle =b*h
b=base
h=height
area of a rectangle=6m*3m=18m^2
area of a semi circle=(pi*r^2)/2
r=radius
area of a semi circle==(3.14*(3m)^2)/2=14.13m^2
area of the figure=6m^2+18m^2+14.13m^2=38.13m^2
the answer is 38.13m^2
