when there is a constant unbalanced force applied in the opposite direction as the motion, speed will __________ and acceleratio
1 answer:
You might be interested in
Answer:
0.76
Explanation:
we are given:
radius (r) =5.7 m
speed (s) = 1 revolution in 5.5 seconds
acceleration due to gravity (g) = 9.8 m/s^{2}
coefficient of friction (Uk) = ?
we can get the minimum coefficient of friction from the equation below
centrifugal force = frictional force
m x r x ω^{2} = Uk x m x g
r x ω^{2} = Uk x g
Uk =
where ω (angular velocity) =
= = 1.14
Uk = = 0.76
Answer:
Explanation:
a. Given that:
mass of first & second piece,
mass of 3rd piece,
-velocity of first piece(
) and
as velocity of 2nd piece (
)
Let be velocity of 3rd piece=?
#Vessel is at rest before explosion. Considering conservation of linear momentum:
#Dividing both sides by
#Plug the values:
#So the magnitude of the third piece is:
Magnitude of the 3rd piece is 10.84 m/s
b. To find direction of the magnitude (as an angle relative to the -axis), we find
. The angle is obtained by getting the tan inverse as:
-The direction of the magnitude (angle relative to the x-axis) is 45°
Initially, the spring stretches by 3 cm under a force of 15 N. From these data, we can find the value of the spring constant, given by Hook's law:
where F is the force applied, and
is the stretch of the spring with respect to its equilibrium position. Using the data, we find
Now a force of 30 N is applied to the same spring, with constant k=5.0 N/cm. Using again Hook's law, we can find the new stretch of the spring:
where F is the force applied, and
Now a force of 30 N is applied to the same spring, with constant k=5.0 N/cm. Using again Hook's law, we can find the new stretch of the spring: