A cat dozes on a stationary merry-go-round, at a radius of 5.7 m from the center of the ride. Then the operator turns on the rid
1 answer:
Answer:
0.76
Explanation:
we are given:
radius (r) =5.7 m
speed (s) = 1 revolution in 5.5 seconds
acceleration due to gravity (g) = 9.8 m/s^{2}
coefficient of friction (Uk) = ?
we can get the minimum coefficient of friction from the equation below
centrifugal force = frictional force
m x r x ω^{2} = Uk x m x g
r x ω^{2} = Uk x g
Uk =
where ω (angular velocity) =
= = 1.14
Uk = = 0.76
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With the addition of vectors we can find that the correct answer is:
C) Q> P > R = S > T
The addition of vectors must be done taking into account that they have modulus and direction. The analytical method is one of the easiest methods, the method to do it is:
- Set a Cartesian coordinate system
- Decompose vectors into their components in a Cartesian system
- Perform the algebraic sums on each axis
- Find the resultant vector using the Pythagoras' Theorem to find the modulus and trigonometry to find the direction.
In this exercise indicate that the modulus of all vectors is the same, suppose that the value of the modulus is A.
We fix a Cartesian coordinate system with the horizontal x axis and the vertical y axis, we can see that we do not need to perform any decomposition, so we perform the algebraic sums
Diagram P
x-axis
x = 2A
y-axis
y = 2A
The modulus of the resulting vector can be found with the Pythagorean Theorem
P =
P =
P = 2 √2 A
Diagram Q
x-axis
x = 3A
y-axis
y = A
Resulting
Q =
Q =
Q =
Diagram R
x- axis
x = 0
y-axis
y = 2 A
Resulting
R =
R =
Diagram S
x-axis
x = 2 A
y-axis
y = 0
Resulting
S = 2A
Diagram T
x- axis
x = 0
y-axis
y = 0
Resultant T = 0
We order the diagram from highest to lowest
Q> P> R = S> T
When reviewing the different answers, the correct one is:
C. Q> P> R = S> T
Learn more about adding vectors here:
Answer:
The speed does it head toward the goal = 41.87
Explanation:
Mass = 0.107 kg
Initial velocity ( u ) = 0
Force (F) = 28 N
Time = 0.16 sec
From newton's second law, Force = mass × acceleration
⇒ F = m × a
⇒ 28 = 0.107 × a
⇒ a = 261.7 --------- (1)
This is the value of acceleration.
Final speed of the mass is calculated by the equation V = U + at
⇒ U = 0 because mass in in rest position at start.
⇒ V = a t
Put the values of acceleration and time in above formula we get
⇒ V = 261.7 × 0.16
⇒ V = 41.87
Therefore the speed does it head toward the goal = 41.87