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Setler [38]
3 years ago
11

A child wants to pump up a bicycle tire so that its pressure is 1.2 × 105 pa above that of atmospheric pressure. if the child us

es a pump with a circular piston 0.035 m in diameter, what force must the child exert?
Physics
2 answers:
WINSTONCH [101]3 years ago
7 0
General expression is;
Pressure = Force/Area
In which,
Pressure = Required pressure + Atmospheric pressure = (1.2*10^5) + (101325) = 221325 Pa = 221325 N/m^2

Area = πD^2/4 = π*0.035^2/4 = 9.621*10^-4 m^2

Therefore,
Force, F = Pressure*Area = 221325*9.621*10^-4 = 212.94 N
shepuryov [24]3 years ago
6 0

Answer:

The force exerted by the child is 460.8 N

Explanation:

We have given that pressure P=1.2\times 10^5pa

Radius of the circular piston r = 0.035 m

So area A=\pi r^2=3.14\times 0.035^2=0.003846m^2

We have to find the force exerted by the child

We know that force is given by

Force=pressure\times area

So force will be Force=1.2\times 10^5\times 0.00384=460.8N

So the force exerted by the child is 460.8 N

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A ball is thrown into the air with 100 J of kinetic energy, which is transformed to gravitational potential energy
goblinko [34]

Answer:

Air resistance

Explanation:

Despite the law of conservation of energy stating that energy can neither be created nor destroyed but can only be transformed from one state to another, some energy is usually lost in the process of transformation and its majorly attributed to frictional loss. Friction opposes normal movement hence in air, air resistance tends to reduce the original energy compared to the initial. That is why the final energy in this case is slightly less than the original energy.

3 0
4 years ago
Drawing a shows a displacement vector (450.0 m along the y axis). In this x, y coordinate system the scalar components are Ax 0
Alisiya [41]

Answer:

x ’= 368.61 m,  y ’= 258.11 m

Explanation:

To solve this problem we must find the projections of the point on the new vectors of the rotated system  θ = 35º

            x’= R cos 35

            y’= R sin 35

           

The modulus vector can be found using the Pythagorean theorem

            R² = x² + y²

            R = 450 m

we calculate

            x ’= 450 cos 35

            x ’= 368.61 m

            y ’= 450 sin 35

            y ’= 258.11 m

4 0
3 years ago
Please show work : A particle with mass 2.00 μg and a charge of – 200 nC has a velocity of 3000 m/s in the x-direction. There is
irga5000 [103]

Answer:

 x =4.5 10⁴ m

Explanation:

To find the distance that the particle moves we must use the equations of motion in one dimension and to find the acceleration of the particle we will use Newton's second law

     m = 2.00 mg (1 g / 1000 ug) (1 Kg / 1000g) = 2.00 10-6 Kg

     q = -200 nc (1C / 10 9 nC) = -200 10-9 C

Let's calculate the acceleration

     F = ma

     F = q E

     a = qE / m

     a = -200 10⁻⁹ 1000 / 2.00 10⁻⁶

     a = 1 10² m / s²

Let's use kinematics to find the distance traveled before stopping, where it has zero speed (Vf = 0)

     Vf² = Vo² -2 a x

     0 = Vo² - 2 a x

     x = Vo² / 2a

     x = 3000²/ 2100

     x =4.5 10⁴ m

This is the distance the particule stop, after this distance in the field accelerates in the opposite direction of the initial

Second part

In this case Newton's second law is applied on the y axis

      F -W = 0

      F = w = mg

      E q = mg

      E = mg / q

      E = 2.00 10⁻⁶ 9.8 / 200 10⁻⁹

      E = 9.8 10⁵ C

       

The direction of the field is such that the force on the particle is up, as the particle has a negative charge, the field must be directed downwards F = qE = (-q) E

7 0
4 years ago
How are electromagnetic waves produced? A) An accelerating electric point charge (electron) emits electromagnetic waves. B) A ba
shusha [124]
Hello,

Here is your answer:

The proper answer to this question will be option A "An accelerating electric point charge (electron) emits electromagnetic waves." That's because electromagnetic waves are formed by motion of electrically charged particles (electrons)!

Your answer is A!

If you need anymore help feel free to ask me!

Hope this helps!
8 0
3 years ago
Read 2 more answers
A net force of 10.N accelerates an object at 5.0 m/s^2. What net force would be required to accelerate the same object at 1.0 m/
Leokris [45]

Answer:

I believe the answer is 2.0

Explanation:

4 0
3 years ago
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