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Setler [38]
3 years ago
11

A child wants to pump up a bicycle tire so that its pressure is 1.2 × 105 pa above that of atmospheric pressure. if the child us

es a pump with a circular piston 0.035 m in diameter, what force must the child exert?
Physics
2 answers:
WINSTONCH [101]3 years ago
7 0
General expression is;
Pressure = Force/Area
In which,
Pressure = Required pressure + Atmospheric pressure = (1.2*10^5) + (101325) = 221325 Pa = 221325 N/m^2

Area = πD^2/4 = π*0.035^2/4 = 9.621*10^-4 m^2

Therefore,
Force, F = Pressure*Area = 221325*9.621*10^-4 = 212.94 N
shepuryov [24]3 years ago
6 0

Answer:

The force exerted by the child is 460.8 N

Explanation:

We have given that pressure P=1.2\times 10^5pa

Radius of the circular piston r = 0.035 m

So area A=\pi r^2=3.14\times 0.035^2=0.003846m^2

We have to find the force exerted by the child

We know that force is given by

Force=pressure\times area

So force will be Force=1.2\times 10^5\times 0.00384=460.8N

So the force exerted by the child is 460.8 N

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Calculate the equivalent resistance of the circuit below.
expeople1 [14]

Answer:

30Ω

Explanation:

To calculate the equivalent resistance in the circuit, do the following:

Step 1:

10Ω and 20Ω are in series connection. Therefore their equivalent is: 10 + 20 = 30Ω

Step 2:

The equivalent resistance (30Ω) obtained from the above is in parallel connection with 30Ω resistance shown in the diagram above.

Therefore their equivalent is given by:

1/30 + 1/30 = 2/30 = 1/15.

Now invert to obtain the equivalent

Therefore, the equivalent is 15Ω

Step 3:

Determination of the overall equivalent of the resistance of the circuit.

The new equivalent resistance 15Ω obtained above is in series connection with 15Ω resistance in the diagram above.

Therefore their equivalent is given by:

15Ω + 15Ω = 30Ω

Therefore, the equivalent resistance in the circuit is 30Ω

7 0
3 years ago
Weather balloons appear only partially inflated when launched into the air. Why would scientists do this?
zvonat [6]

The reason weather balloons are only partially inflated is to allow room for the helium in the balloon to expand.

7 0
3 years ago
A cantilever beam with a width b=100 mm and depth h=150 mm has a length L=2 m and is subjected to a point load P =500 N at B. Ca
DerKrebs [107]

Answer:

Explanation:

Given that:

width b=100mm

depth h=150 mm

length L=2 m =200mm

point load P =500 N

Calculate moment of inertia

I=\frac{bh^3}{12} \\\\=\frac{100 \times 150^3}{12} \\\\=28125000\ m m^4

Point C is subjected to bending moment

Calculate the bending moment of point C

M = P x 1.5

= 500 x 1.5

= 750 N.m

M = 750 × 10³ N.mm

Calculate bending stress at point C

\sigma=\frac{M.y}{I} \\\\=\frac{(750\times10^3)(25)}{28125000} \\\\=0.0667 \ MPa\\\\ \sigma =666.67\ kPa

Calculate the first moment of area below point C

Q=A \bar y\\\\=(50 \times 100)(25 +\frac{50}{2} )\\\\Q=250000\ mm

Now calculate shear stress at point C

=\frac{FQ}{It}

=\frac{500*250000}{28125000*100} \\\\=0.0444\ MPa\\\\=44.4\ KPa

Calculate the principal stress at point C

\sigma_{1,2}=\frac{\sigma_x+\sigma_y}{2} \pm\sqrt{(\frac{\sigma_x-\sigma_y}{2} ) + (\tau)^2} \\\\=\frac{666.67+0}{2} \pm\sqrt{(\frac{666.67-0}{2} )^2 \pm(44.44)^2} \ [ \sigma_y=0]\\\\=333.33\pm336.28\\\\ \sigma_1=333.33+336.28\\=669.61KPa\\\\\sigma_2=333.33-336.28\\=-2.95KPa

Calculate the maximum shear stress at piont C

\tau=\frac{\sigma_1-\sigma_2}{2}\\\\=\frac{669.61-(-2.95)}{2}  \\\\=336.28KPa

6 0
3 years ago
A person walks 12 meters to the west and then 16 meters back to the east. what is the distance covered and the direction of disp
devlian [24]
The distance is 28 meters and the direction of displacement is East I think
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3 years ago
Waves are created on the surface of water when we drop a stone into it. Similarly you must have seen the waves generated on a st
antoniya [11.8K]

Answer:

gdfhf

Explanation:

  1. jjjjcjbwwfbooob#kkkkkkkki!vdvdiiiiiibl#dnqljuwhgeyehrhrygrgdyhehegegeggegegegeegegegevegwgegegegsjkegsygegdydheheyrteeeudgeedyeyrf
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