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Juliette [100K]
3 years ago
12

3. Given PQ = 7x - 3 and QR = 32 – 2x and PR = 59. What is the value of x? What is the value of PQ? What is the value of QR? Be

sure to show your work and all three answers.
Mathematics
2 answers:
olga2289 [7]3 years ago
5 0

Answer:

wag po kayo mag bibigay ng points na marami

Kasi ma iiscam po kayo

nydimaria [60]3 years ago
5 0

Answer:

  • See below

Step-by-step explanation:

We assume Q is between P and R.

<u>According to segment addition postulate we have:</u>

  • PQ + QR = PR

<u>Substitute values and solve for x:</u>

  • 7x - 3 + 32 -2x = 59
  • 5x + 29 = 59
  • 5x = 30
  • x = 6

<u>Find PQ:</u>

  • PQ = 7*6 - 3 = 42 - 3 = 39 units

<u>Find QR:</u>

  • QR = 32 - 2*6 = 32 - 12 = 20 units

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I dont understand how to find Which ordered pair is a solution of the equation? y=8x+3
WARRIOR [948]

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Step 1:

To find ordered pair solutions, you could create an x and y graph and fill out the x side. Then, plug in an x number to get your y number and graph the ordered pairs to see if they give you a straight line. I'm going to use these numbers: -1, 0, 1, and 2.

...x...|...y...

\left[\begin{array}{ccc}-1&?\\0&?\\1&?\\2&?\end{array}\right]

Now, let's plug in -1 into the equation first to see what we get for y.

y=8(-1)+3\\y=-8+3\\y=-5\\(-1,-5)

-5 is our y if x was -1.

We do the same for the other three numbers.

y=8(0)+3\\y=0+3\\y=3\\(0,3)

y=8(1)+3\\y=8+3\\y=11\\(1,11)

y=8(2)+3\\y=16+3\\y=19\\(2,19)

Step 2:

With all that done, we can now fill out our table and graph the points.

....x...|...y....

\left[\begin{array}{ccc}-1&-5\\0&3\\1&11\\2&19\end{array}\right]

If you graph these points on graph paper / a graphing website, you will see that these points go in a straight line. If you are given an ordered pair already (for example: (3,5)), then all you have to do is plug in the x into the equation (3) and see if the outcome is true (5).

5=8(3)+3\\5=24+3\\5\neq 27

Since they don't equal each other, then (3,5) is false.

Here is the graph for the table above. I hope I helped you!

8 0
3 years ago
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