Answer:using elimination to solve for x
9x +6y = 3*134 | Multiplying 1st equation by 3
-4x -6y = -2*146 | Multiplying 2nd equation by -2
5x = 3*134 - 2*146
5x = $110
x = $22, the cost of the youth ticket
Step-by-step explanation:This question Sets Up two equations with 2 unknowns
Let x and y represent the cost of the youth and adult ticket respectively
Question states***
3x + 2y = $134
2x + 3y = $146
180-90=3x
90=3x
X=30
90+x+y=180
90+30+y=180
120+y=180
Y=60
9514 1404 393
Answer:
(a) 6² +3² +1² +1² = 47
(b) 5² +4² +2² +1² +1² = 47
(c) 3³ +4² +2² = 47
Step-by-step explanation:
It can work reasonably well to start with the largest square less than the target number, repeating that approach for the remaining differences. When more squares than necessary are asked for, then the first square chosen may need to be the square of a number 1 less than the largest possible.
The approach where a cube is required can work the same way.
(a) floor(√47) = 6; floor(√(47 -6^2)) = 3; floor(√(47 -45)) = 1; floor(√(47-46)) = 1
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(b) floor(√47 -1) = 5; floor(√(47-25)) = 4; ...
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(c) floor(∛47) = 3; floor(√(47 -27)) = 4; floor(√(47 -43)) = 2
Normally it is x ininput and f(x)=y
solve for y and replace y with f(x)
minus 5x from both sides
2y=10-5x
divide both sides by 2
y=5-2.5x
f(x)=5-2.5x
Answer:
1.$3÷12=0.25
each egg would cost 25 cents
2.12×18=216
216×25=5,400