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Vera_Pavlovna [14]
3 years ago
11

Celeste is making fruit baskets for a local hospital. The directions say to use 5 apples for every 6 oranges. Celeste is filling

her baskets with 2 apples for every 3 oranges. Complete the tables to find equivalent ratios. Circle two columns, one in each table, in which the number of oranges is the same.
apples 5 apples 2
oranges 6 oranges 3
Mathematics
1 answer:
MariettaO [177]3 years ago
8 0

Answer:

A. Equivalent ratios of 5:6

We multiply both the numerator and the denominator by the same number, this way:

<u>10:12 , 15:18, 20:24, 25:30</u>

B. Equivalent ratios of 2:3

We multiply both the numerator and the denominator by the same number, this way:

<u>4:6 , 6:9, 8:12, 10:15, 12:18</u>

C. We have the same number of oranges at:

<u>10:12 and 8:12</u>

<u>15:18 and 12:18</u>

<u>Like Celeste decided not to follow the directions, she's actually using less apples than expected to fill the baskets.</u>

Step-by-step explanation:

1. Let's check all the information provided to answer the question correctly:

Ratio that the local hospital say to Celeste to use : 5 apples for every 6 oranges

Ratio that Celeste is actually using: 2 apples for every 3 oranges

2.  Complete the tables to find equivalent ratios.

A. Equivalent ratios of 5:6

We multiply both the numerator and the denominator by the same number, this way:

10:12 , 15:18, 20:24, 25:30

B. Equivalent ratios of 2:3

We multiply both the numerator and the denominator by the same number, this way:

4:6 , 6:9, 8:12, 10:15, 12:18

3. Circle two columns, one in each table, in which the number of oranges is the same.

We have the same number of oranges at:

10:12 and 8:12

15:18 and 12:18

Like Celeste decided not to follow the directions, she's actually using less apples than expected to fill the baskets.

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A coin bank that excepts only nickels and dimes contains $9.15. There are three more than twice as many nickels as there are dim
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45 dimes and 93 nickels were in bank

<em><u>Solution:</u></em>

Let "n" be the number of nickels

Let "d" be the number of dimes

We know that,

value of 1 nickel = $ 0.05

value of 1 dime = $ 0.10

<em><u>Given that There are three more than twice as many nickels as there are dimes</u></em>

Number of nickels = 3 + 2(number of dimes)

n = 3 + 2d ---- eqn 1

<em><u>Also given that coin bank that excepts only nickels and dimes contains $9.15</u></em>

number of nickels x value of 1 nickel + number of dimes x value of 1 dime = 9.15

n \times 0.05 + d \times 0.10 = 9.15

0.05n + 0.10d = 9.15  ---- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Substitute eqn 1 in eqn 2

0.05(3 + 2d) + 0.10d = 9.15

0.15 + 0.1d + 0.10d = 9.15

0.2d = 9

<h3>d = 45</h3>

From eqn 1

n = 3 + 2(45)

n = 3 + 90 = 93

<h3>n = 93</h3>

Thus 45 dimes and 93 nickels were in bank

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