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Vera_Pavlovna [14]
3 years ago
11

Celeste is making fruit baskets for a local hospital. The directions say to use 5 apples for every 6 oranges. Celeste is filling

her baskets with 2 apples for every 3 oranges. Complete the tables to find equivalent ratios. Circle two columns, one in each table, in which the number of oranges is the same.
apples 5 apples 2
oranges 6 oranges 3
Mathematics
1 answer:
MariettaO [177]3 years ago
8 0

Answer:

A. Equivalent ratios of 5:6

We multiply both the numerator and the denominator by the same number, this way:

<u>10:12 , 15:18, 20:24, 25:30</u>

B. Equivalent ratios of 2:3

We multiply both the numerator and the denominator by the same number, this way:

<u>4:6 , 6:9, 8:12, 10:15, 12:18</u>

C. We have the same number of oranges at:

<u>10:12 and 8:12</u>

<u>15:18 and 12:18</u>

<u>Like Celeste decided not to follow the directions, she's actually using less apples than expected to fill the baskets.</u>

Step-by-step explanation:

1. Let's check all the information provided to answer the question correctly:

Ratio that the local hospital say to Celeste to use : 5 apples for every 6 oranges

Ratio that Celeste is actually using: 2 apples for every 3 oranges

2.  Complete the tables to find equivalent ratios.

A. Equivalent ratios of 5:6

We multiply both the numerator and the denominator by the same number, this way:

10:12 , 15:18, 20:24, 25:30

B. Equivalent ratios of 2:3

We multiply both the numerator and the denominator by the same number, this way:

4:6 , 6:9, 8:12, 10:15, 12:18

3. Circle two columns, one in each table, in which the number of oranges is the same.

We have the same number of oranges at:

10:12 and 8:12

15:18 and 12:18

Like Celeste decided not to follow the directions, she's actually using less apples than expected to fill the baskets.

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Let vons market receive x  loaves. Then savemart received x+12 loaves and Ralphs received x + 12 + 6 = x + 18 loaves, Therefore:-

x + x + 12 + x + 18 = 180

3x + 30 = 180

3x = 150

x = 150/3 = 50  

So vons received 50, savemart received 62 and ralph's received 68 loves.  Answer


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Answer: a

Step-by-step explanation:

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A study was recently conducted at a major university to estimate the difference in the proportion of business school graduates w
sveta [45]

Answer:

(0.1875-0.274) - 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.1412  

(0.1875-0.274) + 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.0318  

And the 95% confidence interval would be given (-0.1412;-0.0318).  

We are confident at 95% that the difference between the two proportions is between -0.1412 \leq p_A -p_B \leq -0.0318

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

p_A represent the real population proportion for business  

\hat p_A =\frac{75}{400}=0.1875 represent the estimated proportion for Business

n_A=400 is the sample size required for Business

p_B represent the real population proportion for non Business

\hat p_B =\frac{137}{500}=0.274 represent the estimated proportion for non Business

n_B=500 is the sample size required for non Business

z represent the critical value for the margin of error  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})  

Solution to the problem

The confidence interval for the difference of two proportions would be given by this formula  

(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}  

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=1.96  

And replacing into the confidence interval formula we got:  

(0.1875-0.274) - 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.1412  

(0.1875-0.274) + 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.0318  

And the 95% confidence interval would be given (-0.1412;-0.0318).  

We are confident at 95% that the difference between the two proportions is between -0.1412 \leq p_A -p_B \leq -0.0318

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Step-by-step explanation:

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