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1 year ago

I need help please LOL

Mathematics

1 answer:

zysi [14]1 year ago

7 0

The answer is 5, the 2 are disqualified and 5 remains

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If 4x - 8 = 4 , find the value of x

Wittaler [7]

Answer:

x=3

Step-by-step explanation:

4x-8=4

4x=12

4x/4=12/4

x=3

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2 years ago

Read 2 more answers

A spinner is divided into five congruent sections, numbered 1 through 5. If the arrow on the spinner is spun, what is the probab

Snowcat [4.5K]

D.2/5 because 3/5 are odd so the remaining 2 are even so 2/5 are not odd!

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2 years ago

Which unit would you use to measure the amount of water in a bathtub?

zepelin [54]

Liters the rest are to small and kg is for solids

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2 years ago

Frank and his mom are planting vegetables in their garden. Frank has finished planting 8 rows of carrots so far and is planting

Yuliya22 [10]

Answer:

It will take 3 hours. They will both have completed 11 rows.

Step-by-step explanation:

1 row of carrots per hour = frank

3 rows of tomatoes per hour = frank's mom

right now, this is how many they have completed

frank - 8 rows

mom - 2 rows

1st hour

f - 9

m - 5

2nd hour

f - 10

m - 8

3rd hour

f - 11

m - 11

8 0

1 year ago

The distribution of SAT II Math scores is approximately normal with mean 660 and standard deviation 90. The probability that 100

gayaneshka [121]

Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

In this problem:

The mean is of 660, hence $\mu = 660$ .

The standard deviation is of 90, hence $\sigma = 90$ .

A sample of 100 is taken, hence $n = 100, s = \frac{90}{\sqrt{100}} = 9$ .

The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{670 - 660}{9}$

$Z = 1.11$

$Z = 1.11$ has a p-value of 0.8665.

1 - 0.8665 = 0.1335.

0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213

7 0

1 year ago