Answer:
HCl < CH₃COOH < NH₃ < NaOH
Explanation:
Given compounds:
Acetic acid: CH₃COOH
Ammonia; NH₃
Hydrochloric acid: HCl
Sodium hydroxide: NaOH
All the solutions are of the same molarity which is 0.1M. We need to see how these compounds dissociate to form solutions in order to establish their pH value:
For Acetic acid;
CH₃COOH + H₂O ⇄ H₃O⁺ + CH₃COO⁻
Acetic acid is a weak acid and it ionizes slightly in solutions. It would have a pH close to 7
For Ammonia;
NH₃ + H₂O ⇄ NH₄⁺ + OH⁻
Ammonia is a weak base and it ionizes slightly in solutions. It sets up an equilibrium in the process. It's would be slightly above 7
For HCl:
HCl + H₂O → H₃O⁺ + Cl⁻
HCl is a strong acid and ionizes completely in solutions. It has a very low pH
For NaOH:
NaOH → Na⁺ + OH⁻
NaOH ionizes also completely in solutions and it breaks down into sodium and hydroxide ions. It is a strong base and it would have a high PH value.
HCl < CH₃COOH < NH₃ < NaOH
This is the trend of increasing pH
Explanation:
its answer is displacement reaction
Answer:
75L of additional water to have a pH 1 solution
Explanation:
The reaction of HCl With NaOH is:
HCl + NaOH → H₂O + NaCl
By using molar mass of each reactant you can know how many moles will react, thus:
HCl: 364.6g HCl ₓ (1mol / 36.46g) = 10 moles HCl
NaOH: 80g NaOH ₓ (1mol / 40g) = 2 moles NaOH
That means after the reaction will remain in solution, 10-2 = 8 moles of HCl = 8 moles of H⁺ (In water, HCl dissociates as H⁺ and Cl⁻ ions).
A solution with pH = 1 contains:
pH = -log [H⁺]
1 = -log [H⁺]
0.1M = [H⁺]
As molarity, M is the ratio between moles and liters and you want a solution 0.1M having 8 moles of H⁺ you require:
0.1M = 8 moles H⁺ / 80L
As the student combines the solution with 5L of water, you require
<h3>75L of additional water to have a pH 1 solution</h3>
Answer:
D
Explanation:
I think but it is an better attempt than the other guy answer.
Answer:
An external stimuli is a stimulus that comes from outside an organism and causes a reaction.An internal stimuli is a stimulus that comes from inside an organism.
