Answer:
There will be produced 1.89x10²⁴ atoms of Ag
Explanation:
This is the reaction:
Cu + 2 AgNO₃ ⇒ Cu(NO₃)₂ + 2 Ag
1 mol of copper reacts with 2 moles of silver nitrate to produce solid silver and 1 mol of copper nitrate.
Ratio is 1:2 so from the moles I have of Cu, I'll produce the double of moles of silver.
100 g / 63.55 g / m = 1.57 moles of Cu
1.57 moles of Cu will produce 3.14 moles of Ag.
Let's calculate the number of atoms, by NA
1 mol of Ag has NA atoms (6.02x10²³)
3.14 moles of Ag will have (3.14 . NA) = 1.89x10²⁴ atoms of Ag
