Question

1) According to the balanced chemical equation below; how many atoms of silver (Ag) will be produced from 100 g of copper (Cu) with excess silver nitrate (AgNO3)? Cu + 2 AgNO3 ⇒ Cu(NO3) 2 + 2 Ag

Answer 1

Answer:

There will be produced 1.89x10²⁴ atoms of Ag

Explanation:

This is the reaction:

Cu + 2 AgNO₃ ⇒ Cu(NO₃)₂ + 2 Ag

1 mol of copper reacts with 2 moles of silver nitrate to produce solid silver and 1 mol of copper nitrate.

Ratio is 1:2 so from the moles I have of Cu, I'll produce the double of moles of silver.

100 g / 63.55 g / m = 1.57 moles of Cu

1.57 moles of Cu will produce 3.14 moles of Ag.

Let's calculate the number of atoms, by NA

1 mol of Ag has NA atoms (6.02x10²³)

3.14 moles of Ag will have (3.14  . NA) = 1.89x10²⁴ atoms of Ag