Find the intersection of the following sets.<br><br>a= 1,2,3,4,5,6,7,8 b= 2,4,6,8,10<br>
Neporo4naja [7]
{2,4,6,8}
Intersection means common elements in both sets
1 foot is 12 inches which makes 14 1.2
6.6-1.2= 5'4 george
richard is 6'0
Given :
The diagonals of rhombus ABCD intersect at E.
∠CAD = 20°.
To Find :
The angle ∠CDA.
Solution :
We know, diagonals of a rhombus bisects each other perpendicularly.
So, ∠DEA = 90°.
In triangle ΔEAD :
∠EAD + ∠AED + ∠EDA = 180°
20° + 90° + ∠EDA = 180°
∠EDA = 70°
Now, we know diagonal of rhombus also bisect the angle between two sides .
So, ∠CDA = 2∠EDA
∠CDA = 2×70°
∠CDA =140°
Therefore, ∠CDA is 140°.
This is the isosceles right triangle, the diagonal of a square, the thing that so upset the Pythagoreans. The two sides and diagonal of a square are in ratio 
so we get
We could have also gotten this using Trig:
Or by recognizing u=v because remaining angle is 45 so this must be isosceles so
