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3 years ago

Is preferable a high percent error or a low percent error?

Chemistry

1 answer:

klio [65]3 years ago

6 0

Explanation:

Percent errors tells you how big your errors are when you measure something in an experiment. Smaller percent errors mean that you are close to the accepted or real value. For example, a 1% error means that you got very close to the accepted value, while 45% means that you were quite a long way off from the true value.

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A student dissolves of styrene in of a solvent with a density of . The student notices that the volume of the solvent does not c

raketka [301]

Answer:

0.576M and 0.655m

Explanation:

<em>...Dissolves 15.0g of styrene (C₈H₈) in 250.mL of a solvent with a density of 0.88g/mL...</em>

<em />

Molarity is defined as moles of solute (Styrene in this case) per liter of solution whereas molality is the moles of solute per kg of solvent. Thus, we need to find the moles of styrene, the volume in liters of the solution and the mass in kg of the solvent as follows:

<em>Moles styrene:</em>

Molar mass C₈H₈:

8C = 12.01g/mol*8 = 96.08g/mol

8H = 1.005g/mol* 8 = 8.04g/mol

96.08g/mol + 8.04g/mol = 104.12g/mol

Moles of 15.0g of styrene are:

15.0g * (1mol / 104.12g) = 0.144 moles of styrene

<em>Liters solution:</em>

250mL * (1L / 1000mL) = 0.250L

<em>kg solvent:</em>

250mL * (0.88g/mL) * (1kg / 1000g) = 0.220kg

Molarity is:

0.144 moles / 0.250L =

Molality is:

0.144 moles / 0.220kg =

8 0

3 years ago

How many molecules of oxygen are produced when a sample of 38.9 g of water is decomposed by electricity?

statuscvo [17]

Answer:

A) $6.5\times 10^{23}\ \text{molecules}$

Explanation:

m = Mass of water = 38.9

M = Molar mass of water = 18 g/mol

$N_A$ = Avogadro's number = $6.022\times 10^{23}\ \text{mol}^{-1}$

The reaction of electrolysis would be

$2H_2O(l)\rightarrow 2H_2(g)+O_2(g)$

Number of moles of $H_2O$

$n=\dfrac{m}{M}\\\Rightarrow n=\dfrac{38.9}{18}\ \text{mol}$

From the reaction it can be seen that 2 moles of $H_2O$ gives 1 mole of $O_2$

So, number of moles of $O_2$ produced is

$\dfrac{38.9}{18}\times \dfrac{1}{2}=1.081\ \text{mol}$

Number of molecules

$1.081N_A=1.081\times 6.022\times 10^{23}\\ =6.5\times 10^{23}$

So, $6.5\times 10^{23}\ \text{molecules}$ of oxygen is produced.

8 0

3 years ago

Can I get some help, I'm bad at science

Elena L [17]

I know the answer to your question but if you want me to answer this question first, I need your help with my question "How do I solve number 12? Quick please I need help ASAP!!!"

7 0

3 years ago

Read 2 more answers

How many molecules are there in 1024 grams of Na2SO4?

tino4ka555 [31]

Answer:

1.91 x 450 molecules

Explanation:

4 0

3 years ago

A solution is prepared by dissolving 16.90 g of ordinary sugar (sucrose, C12H22O11, 342.3 g/mol) in 40.90 g of water. Calculate

katrin2010 [14]

Answer:

Explanation:

The boiling point will increase due to dissolution of sugar in water . Increase in boiling point ΔT

ΔT = Kb x m , where Kb is molal elevation constant water , m is molality of solution

Kb for water = .51°C /m

moles of sugar = 16.90 / 342.3

= .04937 moles

m = moles of sugar / kg of water

= .04937 / .04090

= 1.207

ΔT = Kb x m

= .51 x 1.207

= .62°C .

So , boiling point of water = 100.62°C .

8 0

3 years ago