Answer:
because that is the last group the ones before it are more reactive im sorry if this not what you were looking for.
Answer:
PbBr2 + 2HCl → 2HBr + PbCl2. Reaction Information. Lead(Ii) Bromide + Hydrogen Chloride = Hydrobromic Acid + Cotunnite. Reaction Type.
Explanation:
hope this helps
Answer:
- <em>The oxidation state of chromium in K₂Cr₂O₇</em> is<u> 6⁺ (i.e. + 6).</u>
Explanation:
You can calculate the <em>oxidation number</em> of most elements following some simple rules.
This is how you do it for chromium in K₂Cr₂O₇.
1) Rule: in a neutral compound the net oxidation number is zero (0).
Hence, sum of the oxidation numbers of K, Cr and O in K₂Cr₂O₇ is 0.
2) Rule: The most common oxidation number of oxygen in compounds, except in peroxides, is 2 ⁻ (negative 2).
3) Rule: the most common oxidation state of alkali metals is 1⁺ (positive 1)
4) Rule: multiply each oxidation state by the corresponding number of atoms in the compound (the subscripts)
↑ ↑ ↑
K Cr O
Hence, the oxidation number of chromium in this compound is 6⁺.
Answer:
C. C₆H₁₂O₂
Explanation:
Step 1: Count the number of H atoms
12 H atoms present
Step 2: Count the number of C atoms
6 C atoms present
Step 3: Count the number of O atoms
2 O atoms present
Step 4: Combine
C₆H₁₂O₂
Answer:
I don't think the question is complete