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lesantik [10]
3 years ago
11

Point A is (5, 7).

Mathematics
1 answer:
spin [16.1K]3 years ago
5 0

The coordinate of point B is at (29, -15): Option C is correct.

The formula for calculating the midpoint of two points is expressed as:

M(x, y) = {\frac{x_2+x_1}{2}, \frac{y_2+y_1}{2}}

Given the coordinate points

A is (5, 7).

B is (x, y).

M is (17, -4)

Substituting into the formula to get x and y

17 = 5+x/2

5+x = 34

x = 34 - 5

x = 29

Get the value of y. Similarly;

-4 = 7+y/2

-8 = 7+y

y = -8-7

y = -15

Hence the coordinate of point B is at (29, -15)

Learn more here: brainly.com/question/13989426

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4 years ago
. William fills 1/3 of a water bottle in 1/6 of a minute. How much time will it
Alex Ar [27]

Answer:

It will take him

\frac{1}{2}

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Step-by-step explanation:

I'm really not sure this is right but..

we can solve using proportions. Cross-multiply and divide.

\frac{ \frac{1}{3} of \: a \: water \: bottle}{\frac{1}{6} minute} \:  =  \frac{ \frac{3}{3} of \: a \: water \: bottle}{x}  \\  \\  \frac{ \frac{1}{6} }{ \frac{1}{3} }  =  \frac{ \frac{1}{3} x}{ \frac{1}{3} }  \\  \\  \frac{1}{2}  = x

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3 years ago
Which of the following is carried by the blood and then is eliminated from the body? A. Carbon dioxide B. Ammonia C. Heat D.All
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Answer:

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Step-by-step explanation:

7 0
3 years ago
Match the equation to the graph where n is the Number of Burgers and C is the cost.
Softa [21]

Answer:

How did life during the Industrial Revolution differ in the North and the South?  

In what ways did the Industrial Revolution make life better?

How did it make life more difficult? How did life during the Industrial Revolution differ in the North and the South?  

In what ways did the Industrial Revolution make life better?

How did it make life more difficult?

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The length of a photograph is 1 cm less than twice the width. The area is 91cm^2. find the width and length.
maksim [4K]

Answer:

Width=6.5 cm

Length=12 cm

Step-by-step explanation:

Step 1: Express the lengths and widths

Width=w

Length=l, but 1 cm less than twice the width=(2×w)-1=2 w-1

Step 2: Solve for the length and width

A=L×W

where;

A=area of the photograph

L=length of the photograph

W=width of the photograph

In our case;

A=91 cm²

L=2 w-1

W=w

91=(2 w-1)w

2 w²-w=91

2 w²-w-91=0, is a quadratic equation

solve for w

w={-1±√(-1²-4×2×-91)}/(2×2)

w=(-1±27)/4

w=(27-1)/4=6.5, or (-1-27)/4=-8

Take w=6.5 cm

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Width=6.5 cm

Length=12 cm

6 0
3 years ago
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