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Vlad [161]
3 years ago
13

Solve for the value of n.

Mathematics
2 answers:
stellarik [79]3 years ago
8 0

Answer:

n=8

Step-by-step explanation:

9n=8n+8

n=8

{vertical angles are equal}

allochka39001 [22]3 years ago
4 0

Answer:

n = 8

Step-by-step explanation:

Two angles are vertical angles if they are opposite angles formed by the intersection of two lines. Vertical angles are congruent.

Given that  m < (9n)° and m < (8n + 8)° are vertical angles, then it means that they have the same measure. Therefore, we can solve for the value of n by establishing the following equation:

9n = (8n + 8)

9n = 8n + 8

Subtract 8n from both sides:

9n - 8n = 8n - 8n + 8

n = 8

To double-check whether we came up with the correct value for n, substitute n = 8 into the equation:

9n = (8n + 8)

9(8) = [8(8) + 8]

72 = 64 + 8

72 = 72 (True statement)

Therefore, the correct answer is n = 8.

Please mark my answers as the Brainliest if you find my explanations/solution helpful :)

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3 years ago
A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 2
Shalnov [3]

Answer:

The expected winnings for a person buying 1 ticket is -0.2.                  

Step-by-step explanation:

Given : A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 25 cents each, find the expected winnings for a person buying 1 ticket.

To find : What are the expected winnings?    

Solution :

There are one first prize, 2 second prize and 20 third prizes.

Probability of getting first prize is \frac{1}{20000}

Probability of getting second prize is \frac{2}{20000}

Probability of getting third prize is \frac{20}{20000}

A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each.

So, The value of prizes is

\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10

If 20000 tickets are sold at 25 cents each i.e. $0.25.

Remaining tickets = 20000-1-2-20=19977

Probability of getting remaining tickets is \frac{19977}{20000}

The expected value is

E=\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10-\frac{19977}{20000}\times 0.25

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3 0
3 years ago
Help me with this please. ​
riadik2000 [5.3K]

9514 1404 393

Answer:

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Step-by-step explanation:

The relevant trig relation is ...

  Tan = Opposite/Adjacent

Filling in the given values gives ...

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Multiplying by 5.9, we have ...

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Step-by-step explanation:

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16 gallons will be burned

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