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Mashcka [7]
3 years ago
6

The sum of two numbers is 20 and their difference is 12.

Mathematics
2 answers:
Leno4ka [110]3 years ago
3 0

Answer:

16 and 4

Step-by-step explanation:

x + y= 20

x -y =12

(add both equal #'s)

2x =32

x = 16

y=4

♡

Lynna [10]3 years ago
3 0

Answer:

4 and 16

Step-by-step explanation:

First, let's find first term using sum formula:

\displaystyle \large{S_n =  \frac{1}{2} n[2a_1 + (n - 1)d]}

We know that d or common difference is 12 and only sum of two terms so n = 2.

\displaystyle \large{S_2 =  \frac{1}{2} (2)[2a_1 + (2- 1)d]} \\  \displaystyle \large{S_2 =  2a_1 +d}

Since sum of two numbers equal 20.

\displaystyle \large{20  - 12=  2a_1 +12 - 12} \\   \displaystyle \large{8=  2a_1 }

From above, subtract both sides by 12, solving for a1.

\displaystyle \large{8=  2a_1 } \\  \displaystyle \large{4=  a_1 }

Therefore our first number is 4.

Finding next number, create an equation:-

\displaystyle \large{4 + a_2 = 20 }  \\  \displaystyle \large{4  - 4 + a_2 = 20  - 4}  \\ \displaystyle \large{ a_2 = 16 }

Another number is 16

So 4 and 16 has 12 as difference because 4+12=16 and 16-12 = 4

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