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algol [13]
2 years ago
9

What is the slope of the proportional relationship, and how can I graph it?

Mathematics
1 answer:
MArishka [77]2 years ago
4 0

Answer:

I would say 5.2 .

Step-by-step explanation:

if I’m wrong, I’m sorry. If I’m right, mark me brainlest!

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There are two laundry trucks One laundry truck visits Roxanne's house every 3 days and another laundry truck visits her neighbor
stealth61 [152]

Answer:

Evey 12 days  both  of the trucks visit on the same day

Step-by-step explanation:

The LCM of 3 and 4 is 12, because 12 is the smallest number that 3 and 4 are both factors for.

5 0
2 years ago
tiana's car travel 111 miles on 3/8 of a tank of gas. how far will she be able to go on a full tank of gas?
kari74 [83]
Turn the 3/8 itto a mixed number and dived it by 111 
3 0
3 years ago
Read 2 more answers
Find and simplify the quotient 2/3 divided by 8/9
Anuta_ua [19.1K]
The answer is 3/4 and it was already simplified
8 0
3 years ago
2.) Use the Slope Intercept Form of a line to find the equation of the line from point C to point D.
mezya [45]

First we need slope

  • C=(0,0)
  • D(7,12)

\\ \sf\longmapsto m=\dfrac{12-0}{7-0}

\\ \sf\longmapsto m=\dfrac{12}{7}

Put D co-ordinates on y=mx+b

\\ \sf\longmapsto 12=\dfrac{12}{7}(7)+b

\\ \sf\longmapsto 12=12+b

\\ \sf\longmapsto b=12-12

\\ \sf\longmapsto b=0

Now

slope intercept form.

\\ \sf\longmapsto y=\dfrac{12}{7}x

  • As b=0
8 0
2 years ago
Read 2 more answers
42:28
gogolik [260]

Answer:

The statements about arcs and angles that are true in the figure are;

1) ∠EFD ≅ ∠EGD

2) \overline{ED}\cong \overline{FD}

3) mFD = 120°

Step-by-step explanation:

1) ∠ECD + ∠CEG + ∠CDG + ∠GDE = 360° (Sum of interior angle of a quadrilateral)

∠CEG = ∠CDG = 90° (Given)

∠GDE = 60° (Given)

∴ ∠ECD = 360° - (∠CEG + ∠CDG + ∠GDE)

∠ECD = 360° - (90° + 90° + 60°) = 120°

∠ECD = 2 × ∠EFD (Angle subtended is twice the angle subtended at the circumference)

120° = 2 × ∠EFD

∠EFD = 120°/2 = 60°

∠EFD ≅ ∠EGD

∠ECD = 120°

∠EGD = 60°

∴∠EGD ≠ ∠ECD

2) Given that arc mEF ≅ arc mFD

Therefore, ΔECF and ΔDCF are isosceles triangles having two sides (radii EC and CF in ΔECF and radii EF and CD in ΔDCF

∠ECF = mEF = mFD = ∠DCF (Given)

∴ ΔECF ≅ ΔDCF (Side Angle Side, SAS, rule of congruency)

\\ \overline{EF}\cong \overline{FD} (Corresponding Parts of Congruent Triangles are Congruent, CPCTC)

∠FED ≅ ∠FDE (base angles of isosceles triangle)

∠FED + ∠FDE + ∠EFD = 180° (sum of interior angles of a triangle)

∠FED + ∠FDE = 180° - ∠EFD = 180° - 60° = 120°

∠FED + ∠FDE = 120° = ∠FED + ∠FED (substitution)

2 × ∠FED  = 120°

∠FED = 120°/2 = 60° = ∠FDE

∴ ∠FED = ∠FDE = ∠EFD =  60°

ΔEFD  is an equilateral triangle as all interior angles are equal

\\ \overline{EF}\cong \overline{FD}\cong \overline{ED} (definition of equilateral triangle)

\overline{ED}\cong \overline{FD}

3) Having that ∠EFD = 60° and ∠CFE = ∠CFD (CPCTC)

Where, ∠EFD = ∠CFE + ∠CFD (Angle addition)

60° = ∠CFE + ∠CFD = ∠CFE + ∠CFE (substitution)

60° = 2 × ∠CFE

∠CFE =60°/2 = 30° = ∠CFD

\overline{CF}\cong \overline{CD} (radii of the same circle)

ΔFCD is an isosceles triangle (definition)

∠CFD ≅ ∠CDF (base angles of isosceles ΔFCD)

∠CFD + ∠CDF + ∠DCF = 180°

∠DCF = 180° - (∠CFD + ∠CDF) = 180° - (30° + 30°) = 120°

mFD = ∠DCF (definition)

mFD = 120°.

5 0
3 years ago
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