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MatroZZZ [7]
2 years ago
8

1x1 so you can get points

Mathematics
2 answers:
Hunter-Best [27]2 years ago
8 0
=1
Thank you for the points <33
CaHeK987 [17]2 years ago
6 0
21 duh easiest question ever lol
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The taxi fare in a city is $3 and then $0•40 for every kilometre travelled.A taxi fare is $9.How far has the taxi travelled​
Mrrafil [7]

Answer:

Step-by-step explanation: you would first subtract the 3 from 9 for a basic fee. And after you would decide 6 by .40 and you would end up traveling 15km

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4 Stretch Your Thinking: Brian has some boxes of paper clips. Some boxes hold 10 clips and some boxes hold 100. He has some pape
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2 years ago
Can someone help me this question please?
pashok25 [27]
Larger number is 32 because if u take 48 minus 16 u get your anwser
5 0
3 years ago
Read 2 more answers
An object is launched at 19.6 m/s from a height of 58.8 m. The equation for the height (h) in terms of time (t) is given by h(t)
beks73 [17]
H(t) = Ho +Vot - gt^2/2

Vo = 19.6 m/s
Ho = 58.8 m
g = 9.8 m/s^2

H(t) = 58.8 + 19.6t -9.8t^2/2 = 58.8 + 19.6t - 4.9t^2

Maximun height is at the vertex of the parabole

To find the vertex, first find the roots.

58.8 + 19.6t - 4.9t^2 = 0

Divide by 4.9

12 + 4t - t^2 = 0

Change sign and reorder

t^2 - 4t -12 = 0 

Factor

(t - 6)(t + 2) =0 ==> t = 6 and t = -2.

The vertex is in the mid point between both roots

Find H(t) for: t = [6 - 2]/2 =4/2 = 2

 Find H(t) for t = 2

H(6) = 58.8 + 19.6(2) - 4.9(2)^2 = 78.4

Answer: the maximum height is 78.4 m
5 0
3 years ago
If a gold bar has a length of 17.78 cm, a width of 9.208 cm, a height of 4.445 cm, and the density of gold is 19.3 g/cm^3, what
kozerog [31]

Answer:

17.78×9.208×4.445=727.7275768

D=mass÷volume

mass=density×volume

mass=19.3g/cm3×727,7275768=14045,14223224=14045grams

4 0
2 years ago
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