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3 years ago

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The graphs below have the same shape. What is the equation of the blue graph? A. g(x) = (x-4)2 - 2 B. g(x) = (x + 4)2 + 2 C. g(x

) = (x - 4)2 + 2 D. g(x) = (x + 4)2 - 2

1 answer:

Doss [256]3 years ago

4 0

Answer:

The answer is D. g(x) = (x+4)^2 - 2

Step-by-step explanation:

This is because f(x) = (x-h)^2 + k

where h = horizontal translations and k = vertical translations

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PLEASEE I NEED HELP I WILL GIVE BRAINLIST :))) ( btw im dump)

Keith_Richards [23]

Step-by-step explanation:

u know u can download math go and u just take a picture and it will give u the answer

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3 years ago

-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10

MaRussiya [10]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

(x+y=3<br> (3x+2y=14<br> what is the coordinates for this problem

Ludmilka [50]

<span>3x - 2y + 2y > -14 + 2y </span>

<span>3x + 0 > -14 + 2y </span>

<span>3x > -14 + 2y </span>

<span>3x + 14 > -14 + 14 + 2y </span>

<span>3x + 14 > 0 + 2y </span>

<span>3x + 14 > 2y </span>

<span>(3x + 14)/2 > 2y/2 </span>

<span>(3x + 14)/2 > y*(2/2) </span>

<span>(3x + 14)/2 > y*(1) </span>

<span>(3x + 14)/2 > y </span>

<span>y < (3x + 14)/2 </span>

<span>y < 3x/2 + 14/2 </span>

<span>y < 3x/2 + 7 </span>

<span>y < (3/2)*x + 7 </span>

<span>“y” is LESS THAN (3/2)*x + 7 </span>

<span>the slope intercept form of the inequality is: y < (3/2)*x + 7 </span>

<span>STEP 2: Temporarily change the inequality into an equation by replacing the < symbol with an = symbol. </span>

<span>y < (3/2)*x + 7 </span>

<span>y = (3/2)*x + 7 </span>

<span>STEP 3: Prepare the x-y table using the equation from Step 2. </span>

<span>Using the slope intercept form of the equation from Step 2, choose a value for x, and then compute y for at least three points. </span>

<span>Although you could plot the graph with just two sets of x-y coordinates, you should compute at least three different sets of coordinates points to ensure you have not made a mistake. All three x-y coordinates must lie on the same straight line. If they do not, you have made a mistake. </span>

<span>You can choose any value for x. </span>

<span>For example, (arbitrarily) choose x = -2 </span>

<span>If x = -2, </span>

<span>y = (3/2)*x + 7 </span>

<span>y = (3/2)*(-2) + 7 </span>

<span>y = 4 </span>

4 0

3 years ago

Ok whoever answers this correct will get 100 brainly points

Snezhnost [94]

Answer:

We are given an area and three different widths and we need to determine the corresponding length and perimeter.

The first width that is provided is 4 yards and to get an area of 100 we need to multiply it by 25 yards. This would mean that our length is 25 yards and our perimeter would be 2(l + w) which is 2(25 + 4) = 58 yards.

The second width that is given is 5 yards and in order to get an area of 100 yards we need to multiply by 20 yards. This would mean that our length is 20 yards and our perimeter would be 2(l + w) which is 2(20 + 5) = 50 yards.

The final width that is given is 10 yards and in order to get an area of 100 yards we need to multiply by 10. This would mean that our length is 10 yards and our perimeter would be 2(l + w) which is 2(10 + 10) = 40 yards.

Therefore the field that would require the least amount of fencing (the smallest perimeter) is option C, field #3.

<u><em>Hope this helps!</em></u>

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2 years ago

Read 2 more answers

A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and

mr Goodwill [35]

Answer:

Bias for the estimator = -0.56

Mean Square Error for the estimator = 6.6311

Step-by-step explanation:

Given - A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and X2. The mean is estimated using the formula (3X1 + 4X2)/8.

To find - Determine the bias and the mean squared error for this estimator of the mean.

Proof -

Let us denote

X be a random variable such that X ~ N(mean = 4.5, SD = 7.6)

Now,

An estimate of mean, μ is suggested as

$\mu = \frac{3X_{1} + 4X_{2} }{8}$

Now

Bias for the estimator = E(μ bar) - μ

= $E( \frac{3X_{1} + 4X_{2} }{8}) - 4.5$

= $\frac{3E(X_{1}) + 4E(X_{2})}{8} - 4.5$

= $\frac{3(4.5) + 4(4.5)}{8} - 4.5$

= $\frac{13.5 + 18}{8} - 4.5$

= $\frac{31.5}{8} - 4.5$

= 3.9375 - 4.5

= - 0.5625 ≈ -0.56

∴ we get

Bias for the estimator = -0.56

Now,

Mean Square Error for the estimator = E[(μ bar - μ)²]

= Var(μ bar) + [Bias(μ bar, μ)]²

= $Var( \frac{3X_{1} + 4X_{2} }{8}) + 0.3136$

= $\frac{1}{64} Var( {3X_{1} + 4X_{2} }) + 0.3136$

= $\frac{1}{64} ( [{3Var(X_{1}) + 4Var(X_{2})] }) + 0.3136$

= $\frac{1}{64} [{3(57.76) + 4(57.76)}] } + 0.3136$

= $\frac{1}{64} [7(57.76)}] } + 0.3136$

= $\frac{1}{64} [404.32] } + 0.3136$

= $6.3175 + 0.3136$

= 6.6311

∴ we get

Mean Square Error for the estimator = 6.6311

6 0

3 years ago