Ask question

Ask question

All categories

2 years ago

12

The graphs below have the same shape. What is the equation of the blue graph? A. g(x) = (x-4)2 - 2 B. g(x) = (x + 4)2 + 2 C. g(x

) = (x - 4)2 + 2 D. g(x) = (x + 4)2 - 2

1 answer:

Doss [256]2 years ago

4 0

Answer:

The answer is D. g(x) = (x+4)^2 - 2

Step-by-step explanation:

This is because f(x) = (x-h)^2 + k

where h = horizontal translations and k = vertical translations

You might be interested in

Becca polled the members of her volleyball team to see what their opinions were regarding the awards banquet. Her results were:

leva [86]

Based on the total number of people who want the steakhouse option, the probability that a student will not want the seafoodbuffet if they want the steakhouse option is 24%

<h3>What is the probability of the students' choice?</h3><h3 />

The probability that a student does not want the seafood buffet given that they want the steakhouse option is:

= Number of people who want steakhouse but not seafood / Total surveyed

Solving gives:

= 9 / (16 + 8 + 9 + 4)

= 9 / 37

= 24%

Full question is:

If a student wants the steakhouse option, what is the probability that they will not want the seafoodbuffet?

Find out more on probability at brainly.com/question/27921932

#SPJ1

8 0

1 year ago

Justin got a sack of Jelly beans in 5 different colors. Half if them were red,1/6 were green,1/6 were yellow,1/12 were orange, a

Mrrafil [7]

Answer:

Total number of Jelly beans in the sack = 72

Number of red beans = 36

Number of green beans = 12

Number of yellow beans = 12

Number of orange beans = 6

Number of black beans = 6

Step-by-step explanation:

Let total number of jelly beans be = $x$

We are given fractions of different colors of beans. To find the exact number of beans we need to multiply the fraction with the total number of beans.

Fraction of total are red beans = $\frac{1}{2}$

Number of red beans = $\frac{1}{2}\times x= \frac{x}{2}$

Fraction of total are green beans = $\frac{1}{6}$

Number of green beans = $\frac{1}{6}\times x= \frac{x}{6}$

Fraction of total are yellow beans = $\frac{1}{6}$

Number of yellow beans = $\frac{1}{6}\times x= \frac{x}{6}$

Fraction of total are orange beans = $\frac{1}{12}$

Number of orange beans = $\frac{1}{12}\times x= \frac{x}{12}$

Number of black beans = 6

Total number of beans can be given as

$\frac{x}{2}+\frac{x}{6}+\frac{x}{6}+\frac{x}{12}+6$

Since we assumed total number of beans to be $x$ , so we have.

$\frac{x}{2}+\frac{x}{6}+\frac{x}{6}+\frac{x}{12}+6=x$

Multiplying each term by 12 to remove fractions.

$(12\times\frac{x}{2})+(12\times\frac{x}{6})+(12\times\frac{x}{6})+(12\times\frac{x}{12})+(12\times6)=12\times x$

$6x+2x+2x+x+72=12x$

combining like terms.

$11x+72=12x$

Subtracting both sides by $11x$

$11x+72-11x=12x=11x$

$72=x$

∴ $x=72$

Total number of Jelly beans in the sack = 72

Number of red beans = $\frac{1}{2}\times 72= 36$

Number of green beans = $\frac{1}{6}\times 72= 12$

Number of yellow beans = $\frac{1}{6}\times 72= 12$

Number of orange beans = $\frac{1}{12}\times 72= 6$

number of black beans = 6

8 0

3 years ago

Find the surface area of the Rectangular Pyramid. Please see the attachment, of course 45 yards ^2 is not the correct answer. Th

zheka24 [161]

Answer:

Surface area = 39 yards²

Step-by-step explanation:

∵ the surface area of the pyramid = 1/2 pl + base area

Where p = perimeter of the base , l = slant height

∵ Area of the base = 3 × 3 = 9 yards²

∵ Perimeter of the base = 4 × 3 = 12 yards

∵ Slant height = 5 yards

∴ The surface area = 1/2 × 12 × 5 + 9 = 39 yards²

8 0

3 years ago

Read 2 more answers

2 (x+1)=3x-1 how to do this

Norma-Jean [14]

The answer would be x=3

7 0

3 years ago

Oksana_A [137]

9514 1404 393

Answer:

f'(x) = (-6x² -14x -23)/(x² +5x +2)²

f''(x) = (12x³ +42x² +138x +202)/(x² +5x +2)³

Step-by-step explanation:

The applicable derivative formula is ...

d(u/v) = (v·du -u·dv)/v²

__

f'(x) = ((-x² -5x -2)(4x +4) -(2x² +4x -3)(-2x -5))/(-x² -5x -2)²

f'(x) = (-4x³ -24x²-28x -8 +4x³ +18x² +14x -15)/(x² +5x +2)²

f'(x) = (-6x² -14x -23)/(x² +5x +2)²

__

Similarly, the second derivative is the derivative of f'(x).

f''(x) = ((x² +5x +2)²(-12x -14) -(-6x² -14x -23)(2(x² +5x +2)(2x +5)))/(x² +5x +2)⁴

f''(x) = ((x² +5x +2)(-12x -14) +2(6x² +14x +23)(2x +5))/(x² +5x +2)³

f''(x) = (12x³ +42x² +138x +202)/(x² +5x +2)³

4 0

3 years ago