Answer:
B and A
Step-by-step explanation:
What I did for these problems is plug in the numbers listed for the x-value. For example, in your calculator you’d put; (1/2)^3 and that’d get you 1/8. Then, try it for 8^(2 - 3) which is also 1/8. So, (1/2)^3 = 8^(2 - 3).
The same process for the second problem. 16^(2(7/3) -3) = 4^((7/3) + 1). This should give you 101.59…
I hope this helps :)!
<u>Answer:</u>
plz mark me as brainliest ...TOOK ME LONG TIME TO TYPE
answer = CI = 3108 RUPEES
<u>Step-by-step explanation:</u>
i am doing the method in which u find the simple interest of first year then second year.
SI FOR 1ST YEAR= P X R X T / 100
SI = 2700 X 20 X 2 / 3 X 100 ( RATE OF INTEREST IS 20 / 3)
SI = 108000/300
SI = 360
SI FOR SECOND YEAR =
P = 2700 + 360= 3060
SI = 3060 X 20 X 2 / 300
SI= 122400 / 300
SI = 408
COMPOUND INTEREST (CI) = PRINCIPLE + SI OF 2ND YEAR
CI = 2700 + 408
CI = 3108 RUPEES
or u can solve be the method
CI = amount - principle
Amount= principle x (change in ratio) raised to time
***************************************
Answer:
Step-by-step explanation:
Here's how you convert:
The little number outside the radical, called the index, serves as the denominator in the rational power, and the power on the x inside the radical serves as the numerator in the rational power on the x.
A couple of examples:
![\sqrt[3]{x^4}=x^{\frac{4}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E4%7D%3Dx%5E%7B%5Cfrac%7B4%7D%7B3%7D)
![\sqrt[5]{x^7}=x^{\frac{7}{5}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E7%7D%3Dx%5E%7B%5Cfrac%7B7%7D%7B5%7D)
It's that simple. For your problem in particular:
is the exact same thing as ![\sqrt[3]{7^1}=7^{\frac{1}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B7%5E1%7D%3D7%5E%7B%5Cfrac%7B1%7D%7B3%7D)
Answer:
23. 1/5 24.7/10 25. 23/50
Answer:

Step-by-step explanation:
The fraction 26/5 can be simplified to 5 and 1/5, which is between the numbers 5 and 6.
Hope it helps :) and let me know if you want me to elaborate.