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2 years ago

10% of 30 (this is for a quiz, thanks if u can help)

Mathematics

2 answers:

mezya [45]2 years ago

7 0

Answer:

Step-by-step explanation:

3 * 10 = 30

Hope I could help!

Fynjy0 [20]2 years ago

4 0

The answer would be 3, to find this you would do .10 x 30 to get 3

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M. Section 4.1

vlabodo [156]

According to the given function, it is found that fewer than 38.1% of U.S. voters will use punch cards or lever machines starting from the year of 2004.

<h3>What is the function?</h3>

$P(t) = -2.5t + 63.1$

In which t is the number of years after 1994.

It will be fewer than 38.1% when:

$P(t) < 38.1$

Hence:

$-2.5t + 63.1 < 38.1$

$-2.5t < -25$

$2.5t > 25$

$t > 10$

Fewer than 38.1% of U.S. voters will use punch cards or lever machines starting from the year of 2004.

You can learn more about functions at brainly.com/question/25537936

7 0

2 years ago

Among a sample of 55 male soldiers the average shower time was found to be 2.95 minutes and the population standard deviation is

Oksanka [162]

Answer: -3.0593

Step-by-step explanation:

The test statistic for the difference between two population mean (when population standard deviations $\sigma_1\ \&\ \sigma_2$ are known ) is given by :-

$z=\dfrac{\overline{x}_1-\overline{x}_2}{\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}}$

where ,

$n_1\ \&\ n_2$ = Sample sizes taken from two populations 1 and 2.

$\overline{x}_1-\overline{x}_2$ = Difference between two Sample mean.

$\sigma_1\ \&\ \sigma_2$ = Standard deviations of populations 1 and 2.

As per given , we have

$n_1=55\ \&\ n_2=58$

$\overline{x}_1=2.95\ \&\ \overline{x}_2=3.3$

$\sigma_1=0.65\ \&\ \sigma_2=0.56$

We assume that the data follows a normal distribution.

Then, the test statistic will be :-

$z=\dfrac{2.95-3.3}{\sqrt{\dfrac{(0.65)^2}{55}+\dfrac{(0.56)^2}{58}}}\\\\=\dfrac{-0.35}{\sqrt{0.0130887}}\\\\=\dfrac{-0.35}{0.1144059}=3.05928278174\approx-3.0593$