4y(3y + 9)
12y + 36
36 ÷ 12=x=3
-a²-3b³+c²+2b³-c²
= -(3)² - (3×2)³ + (-3)² + (2 × 2)³ - ( -3)²
= 9 - 24 + 9 + 16 - 9
= 1
answer is 1.
I think is D , hope i answer fast enough haha :D
Begin by factoring 2 out of 2x^2 - 2x - 12 equals 0:
2(x^2 - x - 6) = 0
2(x - 3)(x + 2) = 0. 2 is never zero, but x-3 and x+2 can each be set = to 0:
This results in x = 3 and x = -2. The equation is true for these two x-values.
