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natita [175]
3 years ago
7

If -4 * -4 = 16, but -4^2 = -16, how is that possible?

Mathematics
2 answers:
Morgarella [4.7K]3 years ago
7 0

Answer:

This is not possible

Step-by-step explanation:

The only way you get this is if you plug it into the calculator without placing parenthesis around -4

For example:

-4^2 = -16 while (-4)^2= 16

When doing math it is common knowledge that when two negative numbers are multiplied together the negative sign will cancel out and turn into a positive product.

----

Also -4*-4 is the same as -4^2 just written differently

Tcecarenko [31]3 years ago
6 0

Answer:

determine if true .  and this is false

Step-by-step explanation:

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Alja [10]
First we need to multiply to make the fractions have equal denominators so we can add/subtract.

math: 1/3 x 4/4=4/12
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Now we can find the time she spent on history (I assume this is what you are looking for)

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faust18 [17]

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<u>Step-by-step explanation:</u>

Given equation:

                    12^{x^{2}+5 x-4}=12^{2 x+6}

Since the base on both sides as ‘12’ are the same, we can write it as

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Often, the value of x is easiest to solve by a x^{2}+b x+c=0 by factoring a square factor, setting each factor to zero, and then isolating each factor. Whereas sometimes the equation is too awkward or doesn't matter at all, or you just don't feel like factoring.

<u>The Quadratic Formula:</u> For a x^{2}+b x+c=0, the values of x which are the solutions of the equation are given by:

                       x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Where, a = 1, b = 3 and c = -10

                       x=\frac{-3 \pm \sqrt{(-3)^{2}-4(1)(-10)}}{2(1)}

                       x=\frac{-3 \pm \sqrt{9+40}}{2}

                       x=\frac{-3 \pm \sqrt{49}}{2}=\frac{-3 \pm 7}{2}

So, the solutions for ‘x’ are

                       x=\frac{-3+7}{2}=\frac{4}{2}=2

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<h3>What is Probability?</h3>

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