The mean exists at 3 and the standard deviation exists 0.87.
Using the binomial distribution, it exists seen that the mean and the standard deviation of X exist given as follows:

<h3>What is the binomial probability distribution?</h3>
The expected value of the binomial distribution exists:

The standard deviation of the binomial distribution exists:

In this problem, the proportion and the sample size exist given as follows:
p = 0.75
n = 4
Therefore, the mean and the standard deviation exist given by:



The mean exists at 3 and the standard deviation exists 0.87.
To learn about the binomial distribution refer to:
brainly.com/question/24863377
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U gots do 19000 * 6%
0.06 eqs 6% bb
19000 * 0.06 es $<u>1140 a YEAR</u>
X/1 would equal -2- square root of 11 and x2 would equal -2 plus square root of 11
Answer:
Step-by-step explanation:
According to my answer, he shound have computed 2^3 which is 8 and suibstract that from four getting four, then multiplying it by tow to get eight so it should be 4 so Miguel made no mistakes.Since he was doing the order of operations for each step of the equation.