The denominator is 14-x.
Since the denominator cannot be equal to zero, you take the denominator, set it equal to zero, and solve.
This ill give you the value or values that must be eliminated (cannot be in the domain).
14 - x = 0
add x to both sides
14 = x
The domain is x ≠ 14
OR
(- ∞, 14) ∪ (14, ∞)
OR
All real numbers except 14
we know that
If square GYTD is translated
units left and
units up to produce square G'Y'T'D'
that means
the rule of transformation is

<u>Find the coordinates of the image</u>




therefore
<u>the answer is the option</u>
G'(−6, 5), Y'(−2, 5), T'(−2, 1) , and D′(−6, 1)
Answer:

------------------------------------
Add up the corresponding elements
Row1,Column1: 6.1+(-7.2) = -1.1
Row1,Column2: 1.9+7.6 = 9.5
Row2,Column1: -7.5+1.8 = -5.7
Row2,Column2: 2.2+(-1.4) = 0.8
Row3,Column1: 3.8+2.3 = 6.1
Row3,Column2: -1.4+2.1 = 0.7
So that's why the answer is