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kicyunya [14]
3 years ago
10

Here are five number cards. 2. 5 7 8 9 71 One of the cards is removed and the mean average of the remaining four number cards is

6 Which card was removed? You must show your working. Note: Please make sure your final answer says card ...
​

Mathematics
1 answer:
vovangra [49]3 years ago
7 0

Answer

card number 2

5+7+8+9=24/4=6

Step-by-step explanation:

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Find the future amount at the end of two years for a $7000 investment that earns 7% at the end of each year
Ksivusya [100]

Answer:

$8,014.30

Step-by-step explanation:

5 0
3 years ago
Answer these questions:
k0ka [10]
1) Describe the relationship of input and outpunt values for a composite functions.

The composition of the functions f(x) and g(x) is defined as:

(f ° g) (x) = f [g(x) ].

That means that the output of the function g(x) is the input of the function f(x).

2) Is the inverse of a function always a function?

No, the inverse of a function is not always a function.

Remember that a function cannot have two different outputs for one or more input.

The reason is that if the original function has two or more inputs that result in a same output, when you inverse the original function, the outputs of the original are the inputs of the inverse function and the inputs of the original are the outputs of the inverse. That implies that the inverse function would have some inputs related with more than one output, which is the negation of a function.


3 0
4 years ago
20/12, 35/21 do the ratios form a propprtion
JulijaS [17]
Because they both have a ratio of 5:3 or 5/3
5 0
3 years ago
What's the intuition behind the equation 1+2+3+⋯=−1121+2+3+⋯=−112 ?
Aleks [24]
The sum clearly diverges. This is indisputable. The point of the claim above, that

1+2+3+\cdots=-\dfrac1{12}

is to demonstrate that a sum of infinitely many terms can be manipulated in a variety of ways to end up with a contradictory result. It's an artifact of trying to do computations with an infinite number of terms.

The mathematician Srinivasa Ramanujan famously demonstrated the above as follows: Suppose the series converges to some constant, call it C. Then

\begin{matrix}C&=&1&+2&+3&+4&+5&+6&+\cdots\\4C&=&&+4&&+8&&+12&+\cdots\\-3C&=&1&-2&+3&-4&+5&-6&+\cdots\end{matrix}

Now, recall the geometric power series

\displaystyle\sum_{n\ge0}x^n=1+x+x^2+x^3+\cdots=\dfrac1{1-x}

which holds for any |x|. It has derivative

\displaystyle\sum_{n\ge1}nx^{n-1}=1+2x+3x^2+4x^3+\cdots=\dfrac1{(1-x)^2}

Taking x=-1, we end up with

1+2(-1)+3(-1)^2+4(-1)^3+\cdots=1-2+3-4+\cdots=\dfrac14

and so

-3C=\dfrac14\implies C=-\dfrac1{12}

But as mentioned above, neither power series converges unless |x|. What Ramanujan did was to consider the sum 1-2+3-4+\cdots as a limit of the power series evaluated at x=-1:

\displaystyle-3C=\lim_{x\to-1^+}\sum_{n\ge1}nx^{n-1}=\lim_{x\to-1^+}\frac1{(1-x)^2}=\frac14

then arrived at the conclusion that C=-\dfrac1{12}.

But again, let's emphasize that this result is patently wrong, and only serves to demonstrate that one can't manipulate a sum of infinitely many terms like one would a sum of a finite number of terms.
4 0
3 years ago
Four less than a half of a number is 5 find the number
maw [93]
1/2n - 4 = 5
1/2n = 5 + 4
1/2n = 9
n = 9 * 2
n = 18 <==
4 0
4 years ago
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