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docker41 [41]
3 years ago
7

A halyard 12 ft long is cut into two pieces. Use the same variable to express the lengths of the two pieces.

Mathematics
1 answer:
Anarel [89]3 years ago
4 0

Answer:

The length is 6ft if cut in half because 6+6=12 which means 6ft+6ft=12ft

Step-by-step explanation:

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Answer:

We can note that this part of the graph is a linear function. This means that is has a general form: y = mx + c where m is the slop and c is the y-intercept (value of y at x=0). For the slope, we will use the points (0,2) and (3,5) to calculate it as follows: m = (y2-y1)/(x2-x1) = (5-2)/(3-0) = 1 For the y-intercept, we can note that at x=0, the value of y is 2. This means that the equation of the first part of the graph is: y = x + 2

Read more at Answer.Ya.Guru – https://answer.ya.guru/questions/703068-which-rules-define-the-function-graphed-below.html

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Answer:

a) (\sqrt[n]{x}) the n will be 5 the x will be (-32/243)^2.

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d) the answer would be (st)^v/u.

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3 years ago
One study reports that 34​% of newly hired MBAs are confronted with unethical business practices during their first year of empl
MaRussiya [10]

Answer:

z=\frac{0.28 -0.34}{\sqrt{\frac{0.34(1-0.34)}{116}}}=-1.364  

p_v =2*P(Z  

The p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIl to reject the null hypothesis, and we can said that at 5% of significance the proportion of graduates from the previous year claim to have encountered unethical business practices in the workplace is not significant different from 0.34.  

Step-by-step explanation:

1) Data given and notation

n=116 represent the random sample taken

X represent the number graduates from the previous year claim to have encountered unethical business practices in the workplace

\hat p=0.28 estimated proportion of graduates from the previous year claim to have encountered unethical business practices in the workplace

p_o=0.34 is the value that we want to test

\alpha=0.05 represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion is 0.34 or no.:  

Null hypothesis:p=0.34  

Alternative hypothesis:p \neq 0.34  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.28 -0.34}{\sqrt{\frac{0.34(1-0.34)}{116}}}=-1.364  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(Z  

The p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIl to reject the null hypothesis, and we can said that at 5% of significance the proportion of graduates from the previous year claim to have encountered unethical business practices in the workplace is not significant different from 0.34.  

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