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2 years ago

Arrange the following species in order of increasing oxidation number of the sulfur atom:

Chemistry

1 answer:

garri49 [273]2 years ago

4 0

Answer:

HS2

Explanation:

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Show how water can serve as a base by showing the chemical equation of water reacting with hydrochloric acid. g

goldfiish [28.3K]

So, water reacts with hydrochloric acid in the following formula

H2O + HCl —-> H3O+ + Cl-

We can visualize that when the two react, the hydrogen ions is taken on by the water molecule. This satisfies one of the definitions for a base

Bronsted acids = anything that donates a proton (H+ ion)

Bronsted bases = anything that accepts a proton (H+ ion)

So, as we can see, that is exactly what is happening. The Cl- and H+ detach and then the water takes on that extra H+.

H3O+ is what we call a hydronium ion

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3 years ago

Which separation procedure is most likely to happen? Freezing a compound will break it down into elements. Filtering a mixture w

Alona [7]

Answer is: Filtering a mixture will separate it into substances.

Pure substance is made of only one type of atom (element) or only one type of molecule, it has definite and constant composition with distinct chemical properties. Pure substances can be separated chemically, not physically, that is difference between pure substances and mixtures.

Filtration is use for separation of heterogenous mixture, for example, sand and water.

5 0

4 years ago

Read 2 more answers

111111111111111111111111111111

Ronch [10]

Answer:

22222222222222222222

Explanation:

4 0

3 years ago

1) Which pure substance is composed of more than one element?

Zina [86]

Answer:

Explanation:

7 0

3 years ago

Read 2 more answers

Lead (II) carbonate decomposes to give lead (II) oxide and carbon dioxide: PbCO 3 (s) PbO (s) CO 2 (g) ________ grams of lead (I

blsea [12.9K]

Answer:

We will have 7.30 grams lead(II) oxide

Explanation:

Step 1: Data given

Mass of lead (II)carbonate = 8.75 grams

Molar mass PbCO3 = 267.21 g/mol

Step 2: The balanced equation

PbCO3 (s) ⇆ PbO(s) + CO2(g)

Step 3: Calculate moles PbCO3

Moles PbCO3 = mass / molar mass

Moles PbCO3 = 8.75 grams / 267.21 g/mol

Moles PbCO3 = 0.0327 moles

Step 4: Calculate moles PbO

For 1 mol PbCO3 we'll have 1 mol PbO and 1 mol CO2

For 0.0327 moles PbCO3 we'll have 0.0327 moles PbO

Step 5: Calculate mass PbO

Mass PbO = moles PbO * molar mass PbO

Mass PbO = 0.0327 moles * 223.2 g/mol

Mass PbO = 7.30 grams

We will have 7.30 grams lead(II) oxide

7 0

4 years ago