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harina [27]
3 years ago
10

Show how water can serve as a base by showing the chemical equation of water reacting with hydrochloric acid. g

Chemistry
1 answer:
goldfiish [28.3K]3 years ago
8 0
So, water reacts with hydrochloric acid in the following formula

H2O + HCl —-> H3O+ + Cl-

We can visualize that when the two react, the hydrogen ions is taken on by the water molecule. This satisfies one of the definitions for a base

Bronsted acids = anything that donates a proton (H+ ion)

Bronsted bases = anything that accepts a proton (H+ ion)

So, as we can see, that is exactly what is happening. The Cl- and H+ detach and then the water takes on that extra H+.

H3O+ is what we call a hydronium ion
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You are walking on a beach and see a split. Explain how a split could have formed from a rocky headland.
kirza4 [7]

Hello, Lindaparker, a spit  could form from a rocky headland where prevailing winds would blow at an angle to the rocky headland, gradually depositing sand and shingle at that place. A spit is a permanent land form resulting from marine deposition and wind deposition. It is usually a long and narrow accumulation of sand or shingle with one joined to the land and the other end projecting at   a narrow angle out into the sea. Salt marshes sometimes form on the sheltered side of a spit.

8 0
3 years ago
Read 2 more answers
At 55.0 ∘C, what is the vapor pressure of a solution prepared by dissolving 78.4 g of LiF in 253 g of water? The vapor pressure
ddd [48]

Answer:

82.5 mmHg

Explanation:

The vapor pressure of a solution that contains a non-volatile solute will depend on the mole fraction of the solvent and on the vapor pressure of the pure solvent at the same temperature.

P sol=  χsolvent ⋅ P∘solvent, where

Psol - the vapor pressure of the solution

χ solvent - the mole fraction of the solvent

P ∘solvent - the vapor pressure of the pure solvent

Now, the most important thing to realize here is that lithium fluoride,  

LiF , a soluble ionic compound, will dissociate completely in aqueous solution to form lithium cations and fluoride anions.

LiF (aq] → Li+(aq]  + F − (aq]

Notice that every mole of lithium fluoride produces one mole of lithium cations and one mole of fluoride anions.

This means that you get a total of two moles of ions for every one mole of lithium fluoride in the solution.

Use lithium fluoride's molar mass to determine how many moles would be found in the given sample

78.4g⋅ (1 mole LiF /25.94 g)  = 3.022 moles LiF

This means that the solution will contain

3.022 moles LiF ⋅  (2 moles ions /1 mole LiF)  = 6.044 moles ions

Now, water's mole fraction in this solution will be equal to the number of moles of water divided by the total number of moles present in the solution.

To get the number of moles of water, use its molar mass

253  g  ⋅  (1 mole H 2O / 18.015 g) = 14.044 moles H 2O

This means that water's mole fraction will be

χwater = 14.044 moles  / (14.044 +6.044 )moles = 0.6991

The vapor pressure of the solution will thus be

Psol= 0.6991  ⋅ 118 mmHg = 82.5 mmHg

7 0
3 years ago
Amino acids are the building blocks of proteins. The simplest amino acid is glycine (H2NCH2COOH). Draw a Lewis structure for gly
VashaNatasha [74]

Answer:

Explanation:

The lewis structure (indicating all the atoms and patterns provided as hint in the question) of glycine can be seen in the attachment below. While the chemical structure of glycine can be seen below

         H

          |

H₂N - C - C =O

          |      \

         H      OH

The structure (of glycine) above provides a "fair idea" of how the lewis structure will be.

3 0
3 years ago
Please help! This is for a test and I want to have a good grade. Have a great day! :)
elena-s [515]

Answer:

genetic engineering !! :)

Explanation:

also, i love the pfp <3

6 0
3 years ago
Write a balanced overall reaction from these unbalanced half-reactions. ln-&gt;ln3+ cd2+-&gt;cd
DochEvi [55]
Oxidation reaction 
In ---> In³⁺ + 3e ---1)
reduction reaction
Cd²⁺ + 2e ---> Cd ---2)
when balancing the reactions, electrons have to be balanced. to balance the electrons multiple 1st reaction by 2 and 2nd reaction by 3
1) x 2
2) x 3
2In ---> 2In³⁺ + 6e
3Cd²⁺ + 6e ---> 3Cd
add the 2 equations to obtain the overall reaction

2In + 3Cd²⁺ ---> 2In³⁺ + 3Cd
5 0
3 years ago
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